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Pertanyaan

Carilah solusi ( x , y ) bilangan real untuk setiap persamaan kuadrat berikut dan lukiska sketsa grafik penyelesaiannya! { 2 x 2 + 3 y 2 = 23 3 x 2 − 2 y 2 = 15 ​

Carilah solusi  bilangan real untuk setiap persamaan kuadrat berikut dan lukiska sketsa grafik penyelesaiannya!

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D. Wahyu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

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Pembahasan

Diketahui: Misalkan : Dengan mengeliminasikan persamaan (1) dan (2), sehingga Kemudian, subtitusikan nilai ke persamaan (1), sehingga Jadi, solusi adalah (7,3) Grafik Grafik

Diketahui:

2 x squared plus 3 y squared equals 23 3 x squared minus 2 y squared equals 15

Misalkan : u equals x squared v equals y squared

2 u plus 3 v equals 23 space... left parenthesis 1 right parenthesis 3 u minus 2 v equals 15 space... left parenthesis 2 right parenthesis

Dengan mengeliminasikan persamaan (1) dan (2), sehingga

2 u plus 3 v equals 23 space space space left parenthesis x 3 right parenthesis space space up diagonal strike space space space 6 u end strike plus 9 v equals 69 3 u minus 2 v equals 15 space space space left parenthesis x 2 right parenthesis space space up diagonal strike space space 6 u end strike minus 4 v equals 30 space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space top enclose space space space space space space space space space space space 13 v equals 39 space space space space space space space space space space space space space space space space space space space end enclose space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space v equals 39 over 13 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space v equals 3 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space

Kemudian, subtitusikan nilai v ke persamaan (1), sehingga

table attributes columnalign right center left columnspacing 0px end attributes row cell 2 u plus 3 v end cell equals 23 row cell 2 u plus 3 left parenthesis 3 right parenthesis end cell equals 23 row cell 2 u plus 9 end cell equals 23 row cell 2 u end cell equals cell 23 minus 9 end cell row cell 2 u end cell equals 14 row u equals cell 14 over 2 end cell row u equals 7 end table

Jadi,  solusi adalah (7,3)

Grafik

  • table attributes columnalign right center left columnspacing 0px end attributes row cell 2 x squared plus 3 y squared end cell equals 23 row cell negative space Sumbu space x comma space ketika space y end cell equals cell 0 space colon end cell row cell 2 x squared plus 3 left parenthesis 0 right parenthesis squared end cell equals 23 row cell 2 x squared end cell equals 23 row cell x squared end cell equals cell 23 over 2 end cell row x equals cell plus-or-minus square root of 23 over 2 end root end cell row cell x subscript 1 end cell equals cell square root of 23 over 2 space comma space end root space x subscript 2 equals negative square root of 23 over 2 end root end cell row blank blank blank row cell negative Sumbu space y comma space ketika space x end cell equals cell 0 colon end cell row cell 2 left parenthesis 0 right parenthesis plus 3 y squared end cell equals 23 row cell 3 y squared end cell equals 23 row cell y squared end cell equals cell 23 over 2 end cell row y equals cell plus-or-minus square root of 23 over 2 end root end cell row cell y subscript 1 end cell equals cell square root of 23 over 2 space comma space end root space y subscript 2 equals negative square root of 23 over 2 end root end cell row blank blank blank end table
  •  3 x squared minus 2 y squared equals 15 minus Sumbu space x comma space ketika space y equals 0 colon 3 x squared minus 2 left parenthesis 0 right parenthesis squared equals 15 3 x squared equals 15 x squared equals 15 over 3 x squared equals 5 x equals plus-or-minus square root of 5 x subscript 1 equals square root of 5 space space space comma space x subscript 2 equals negative square root of 5 minus Sumbu space y comma space ketika space x equals 0 colon 3 left parenthesis 0 right parenthesis squared minus 2 y squared equals 15 minus 2 y squared equals 15 y squared equals negative 15 over 2 y equals plus-or-minus square root of fraction numerator negative 15 over denominator 2 end fraction end root straight y space tidak space mempunyai space penyelesaian x equals plus-or-minus square root of 5 x subscript 1 equals square root of 5 space space space comma space x subscript 2 equals negative square root of 5

Grafik

 

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Pertanyaan serupa

Carilah semua solusi ( x , y ) bilangan real untuk setiap persamaan kuadrat berikut dan lukiskan sketsa grafik penyelesaianya! { x 2 + y 2 = 25 x 2 − y 2 = 7 ​

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