Carilah nilai f(x) jika f (x)=x+x2 dan f(1)=1

Pertanyaan

Carilah nilai $\style{font-size:14px}{f(x)}$ jika $begin mathsize 14px style f apostrophe left parenthesis x right parenthesis equals square root of x plus fraction numerator 2 over denominator square root of x end fraction end style$ dan $\style{font-size:14px}{f(1)=1}$

F. Ayudhita

Master Teacher

Jawaban terverifikasi

Pembahasan

$f left parenthesis x right parenthesis equals integral open parentheses square root of x plus fraction numerator 2 over denominator square root of x blank end root end fraction close parentheses blank d x$

$f left parenthesis x right parenthesis space equals integral square root of x blank d x plus blank integral fraction numerator 2 over denominator square root of x blank end root end fraction d x$

$f open parentheses x close parentheses equals fraction numerator 1 over denominator 1 half plus 1 end fraction blank x to the power of 1 half plus 1 end exponent plus c plus fraction numerator 2 over denominator negative 1 half plus 1 end fraction blank x to the power of negative 1 half plus 1 end exponent plus c$

$f left parenthesis x right parenthesis space equals space fraction numerator 1 over denominator 3 over 2 end fraction x to the power of 3 over 2 end exponent plus fraction numerator 2 over denominator 1 half end fraction x to the power of 1 half end exponent plus C$

Karena , maka

Sehingga

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