Roboguru

Banyaknya  yang dapat larut dalam 500 mL  0,1 M adalah ... ( = 224 dan  = )

Pertanyaan

Banyaknya Ag subscript 2 Cr O subscript 4 yang dapat larut dalam 500 mL Ag N O subscript 3 0,1 M adalah ...

(italic M subscript r space Ag subscript 2 Cr O subscript 4 = 224 dan K subscript sp space Ag subscript 2 Cr O subscript 4 = 4 cross times 10 to the power of negative sign 12 end exponent)

  1. 2 comma 24 cross times 10 to the power of negative sign 3 end exponent gram space 

  2. 4 comma 48 cross times 10 to the power of negative sign 3 end exponent gram space 

  3. 2 comma 24 cross times 10 to the power of negative sign 8 end exponent gram space 

  4. 4 comma 48 cross times 10 to the power of negative sign 8 end exponent gram space 

  5. 9 comma 96 cross times 10 to the power of negative sign 8 end exponent gram space 

Pembahasan Soal:

Ag N O subscript 3 space rightwards arrow space stack Ag to the power of plus sign with 0 comma 1 space M below space plus space N O subscript 3 to the power of minus sign Ag subscript 2 Cr O subscript 4 space rightwards arrow space stack 2 Ag to the power of plus sign with 0 comma 1 space M below space plus space Cr with O subscript 4 to the power of 2 minus sign s below 
 

K subscript sp equals open square brackets Ag to the power of plus sign close square brackets squared left square bracket N O subscript 3 end subscript superscript negative sign end superscript right square bracket 4 cross times 10 to the power of negative sign 12 end exponent equals left square bracket 0 comma 1 right square bracket squared space s s equals 4 cross times 10 to the power of negative sign 10 end exponent  s equals m over italic M subscript r cross times fraction numerator 1000 over denominator V space open parentheses mL close parentheses end fraction 4 cross times 10 to the power of negative sign 10 end exponent equals m over 224 cross times 1000 over 500 m equals 4 comma 48 cross times 10 to the power of negative sign 8 end exponent space gram 
 

Jadi, jawaban tepat adalah D.space  

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 26 April 2021

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved