Roboguru
SD
SMP
SMA
UTBK/SNBT

Iklan

Pertanyaan

Adjoin dari matriks adalah ...

Adjoin dari matriks open square brackets table row 3 11 2 row cell negative 1 end cell 2 4 row 3 cell negative 2 end cell 1 end table close square brackets adalah ...

  1. open square brackets table row 10 cell negative 15 end cell 40 row 13 cell negative 3 end cell cell negative 14 end cell row cell negative 4 end cell 39 17 end table close square brackets

  2. open square brackets table row 10 13 cell negative 4 end cell row cell negative 15 end cell cell negative 3 end cell 39 row 40 cell negative 14 end cell 17 end table close square brackets

  3. open square brackets table row 10 10 cell negative 4 end cell row cell negative 15 end cell cell negative 3 end cell 39 row 40 cell negative 4 end cell 17 end table close square brackets

  4. open square brackets table row 10 13 cell negative 4 end cell row 15 3 39 row 40 cell negative 14 end cell 17 end table close square brackets

  5. open square brackets table row 10 13 cell negative 40 end cell row cell negative 15 end cell cell negative 3 end cell 39 row 4 cell negative 14 end cell 17 end table close square brackets

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

18

:

02

:

08

Klaim

Iklan

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

A equals open square brackets table row 3 11 2 row cell negative 1 end cell 2 4 row 3 cell negative 2 end cell 1 end table close square brackets K o f space A equals open square brackets table row cell plus open vertical bar table row 2 4 row cell negative 2 end cell 1 end table close vertical bar end cell cell negative open vertical bar table row cell negative 1 end cell 4 row 3 1 end table close vertical bar end cell cell plus open vertical bar table row cell negative 1 end cell 2 row 3 cell negative 2 end cell end table close vertical bar end cell row cell negative open vertical bar table row 11 2 row cell negative 2 end cell 1 end table close vertical bar end cell cell plus open vertical bar table row 3 2 row 3 1 end table close vertical bar end cell cell negative open vertical bar table row 3 11 row 3 cell negative 2 end cell end table close vertical bar end cell row cell plus open vertical bar table row 11 2 row 2 4 end table close vertical bar end cell cell negative open vertical bar table row 3 2 row cell negative 1 end cell 4 end table close vertical bar end cell cell plus open vertical bar table row 3 11 row cell negative 1 end cell 2 end table close vertical bar end cell end table close square brackets K o f space A equals open square brackets table row cell left parenthesis 2 plus 8 right parenthesis end cell cell negative left parenthesis negative 1 minus 12 right parenthesis end cell cell left parenthesis 2 minus 6 right parenthesis end cell row cell negative left parenthesis 11 plus 4 right parenthesis end cell cell left parenthesis 3 minus 6 right parenthesis end cell cell negative left parenthesis negative 6 minus 33 right parenthesis end cell row cell left parenthesis 44 minus 4 right parenthesis end cell cell negative left parenthesis 12 plus 2 right parenthesis end cell cell left parenthesis 6 plus 11 right parenthesis end cell end table close square brackets K o f space A equals open square brackets table row 10 13 cell negative 4 end cell row cell negative 15 end cell cell negative 3 end cell 39 row 40 cell negative 14 end cell 17 end table close square brackets A d j space A equals open parentheses K o f space A close parentheses to the power of T space space space space space space space space space space space space equals open square brackets table row 10 cell negative 15 end cell 40 row 13 cell negative 3 end cell cell negative 14 end cell row cell negative 4 end cell 39 17 end table close square brackets

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

16

Iklan

Gold Icon

Klaim Gold gratis sekarang!

Dengan Gold kamu bisa tanya soal ke Forum sepuasnya, lho.

Pertanyaan serupa

Invers dari matriks adalah ....

2

0.0

Jawaban terverifikasi

Invers dari matriks adalah ....

2

0.0

Jawaban terverifikasi

Iklan

Bentuk umum persamaan parabola adalah y = a x 2 + b x + c . Carilah persamaan parabola yang melalui titik A ( 1 , 9 ) , B ( − 1 , 3 ) , dan C ( − 2 , 6 ) .

3

5.0

Jawaban terverifikasi

Selesaikan sistem persamaan linear tiga variabel berikut dengan cara invers matriks. ⎩ ⎨ ⎧ ​ x + y + z = 8 3 x − y + 3 z = 8 5 x + 2 z = 10 ​

2

4.0

Jawaban terverifikasi

Tentukan invers matriks-matriks berikut! f. K = ⎝ ⎛ ​ 2 − 4 3 ​ 0 − 1 0 ​ − 5 8 7 ​ ⎠ ⎞ ​

5

0.0

Jawaban terverifikasi
Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Download di Google Play

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Bantuan & Panduan

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia