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Invers dari matriks adalah ....

Invers dari matriks undefined adalah ....

  1. begin mathsize 14px style 1 over 37 open parentheses table row 13 cell negative 9 end cell 8 row 9 8 cell negative 3 end cell row cell negative 6 end cell 7 2 end table close parentheses end style 

  2. begin mathsize 14px style 1 over 37 open parentheses table row 13 9 cell negative 6 end cell row cell negative 9 end cell 8 7 row 8 cell negative 3 end cell 2 end table close parentheses end style   

  3. begin mathsize 14px style 1 over 37 open parentheses table row 13 8 8 row cell negative 9 end cell 8 7 row cell negative 6 end cell 7 2 end table close parentheses end style  

  4. begin mathsize 14px style negative 1 over 37 open parentheses table row 13 cell negative 9 end cell cell negative 6 end cell row cell negative 9 end cell 8 7 row 8 cell negative 3 end cell 2 end table close parentheses end style   

  5. begin mathsize 14px style negative 1 over 37 open parentheses table row 13 cell negative 9 end cell 8 row 9 8 cell negative 3 end cell row cell negative 6 end cell 7 2 end table close parentheses end style  

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Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.

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Pembahasan

Diketahui . Kita cari dulu masing-masing nilai minornya lalu kita tentukan kofaktornya. Sehingga kita peroleh matriks kofaktornya adalah Jadi, adjoinnya adalah Selanjutnya, kita cari determinan matriks D dengan metode Sarrus. Kita peroleh diagonal kanan = 1 ∙ 2 ∙ 5 + 0 ∙ ( - 1) ∙ (-1) + 3 ∙ 2 ∙ 3 = 10 + 0 + 18 = 28 diagonal kiri = 3 ∙ 2 ∙ ( - 1) + 1 ∙ ( - 1) ∙ 3 + 0∙ 2∙ 5 = - 6 -3+ 0 = - 9 Sehingga determinannya adalah determinan = diagonal kanan - diagonal kiri = 28- (-9) = 37 Jadi, invers dari matriks D adalah Dengan demikian, jawaban yang tepat adalah B.

Diketahui undefined. Kita cari dulu masing-masing nilai minornya lalu kita tentukan kofaktornya.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight M subscript 11 end cell equals cell open vertical bar table row 2 cell negative 1 end cell row 3 5 end table close vertical bar equals 2 times 5 minus left parenthesis negative 1 right parenthesis times 3 equals 10 plus 3 equals 13 end cell row cell straight C subscript 11 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 1 plus 1 end exponent times straight M subscript 11 end subscript equals left parenthesis negative 1 right parenthesis squared times 13 equals 1 times 13 equals 13 end cell row blank blank blank row cell straight M subscript 12 end cell equals cell open vertical bar table row 2 cell negative 1 end cell row cell negative 1 end cell 5 end table close vertical bar equals 2 times 5 minus left parenthesis negative 1 right parenthesis times left parenthesis negative 1 right parenthesis equals 10 minus 1 equals 9 end cell row cell straight C subscript 12 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 1 plus 2 end exponent times straight M subscript 12 end subscript equals left parenthesis negative 1 right parenthesis cubed times 9 equals left parenthesis negative 1 right parenthesis times 9 equals negative 9 end cell row blank blank blank row cell straight M subscript 13 end cell equals cell open vertical bar table row 2 2 row cell negative 1 end cell 3 end table close vertical bar equals 2 times 3 minus 2 times left parenthesis negative 1 right parenthesis equals 6 plus 2 equals 8 end cell row cell straight C subscript 13 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 1 plus 3 end exponent times straight M subscript 13 end subscript equals left parenthesis negative 1 right parenthesis to the power of 4 times 8 equals 1 times 8 equals 8 end cell row blank blank blank row cell straight M subscript 21 end cell equals cell open vertical bar table row 0 3 row 3 5 end table close vertical bar equals 0 times 5 minus 3 times 3 equals 0 minus 9 equals negative 9 end cell row cell straight C subscript 21 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 2 plus 1 end exponent times straight M subscript 21 end subscript equals left parenthesis negative 1 right parenthesis cubed times left parenthesis negative 9 right parenthesis equals left parenthesis negative 1 right parenthesis times left parenthesis negative 9 right parenthesis equals 9 end cell row blank blank blank row cell straight M subscript 22 end cell equals cell open vertical bar table row 1 3 row cell negative 1 end cell 5 end table close vertical bar equals 1 times 5 minus 3 times left parenthesis negative 1 right parenthesis equals 5 plus 3 equals 8 end cell row cell straight C subscript 22 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 2 plus 2 end exponent times straight M subscript 22 end subscript equals left parenthesis negative 1 right parenthesis to the power of 4 times 8 equals 1 times 8 equals 8 end cell row blank blank blank row cell straight M subscript 23 end cell equals cell open vertical bar table row 1 0 row cell negative 1 end cell 3 end table close vertical bar equals 1 times 3 minus 0 times left parenthesis negative 1 right parenthesis equals 3 plus 0 equals 3 end cell row cell straight C subscript 23 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 2 plus 3 end exponent times straight M subscript 23 end subscript equals left parenthesis negative 1 right parenthesis to the power of 5 times 3 equals left parenthesis negative 1 right parenthesis times 3 equals negative 3 end cell row blank blank blank row cell straight M subscript 31 end cell equals cell open vertical bar table row 0 3 row 2 cell negative 1 end cell end table close vertical bar equals 0 times left parenthesis negative 1 right parenthesis minus 3 times 2 equals 0 minus 6 equals negative 6 end cell row cell straight C subscript 31 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 3 plus 1 end exponent times straight M subscript 31 end subscript equals left parenthesis negative 1 right parenthesis to the power of 4 times left parenthesis negative 6 right parenthesis equals 1 times left parenthesis negative 6 right parenthesis equals negative 6 end cell row blank blank blank row cell straight M subscript 32 end cell equals cell open vertical bar table row 1 3 row 2 cell negative 1 end cell end table close vertical bar equals 1 times left parenthesis negative 1 right parenthesis minus 3 times 2 equals negative 1 minus 6 equals negative 7 end cell row cell straight C subscript 32 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 3 plus 2 end exponent times straight M subscript 32 end subscript equals left parenthesis negative 1 right parenthesis to the power of 5 times left parenthesis negative 7 right parenthesis equals left parenthesis negative 1 right parenthesis times left parenthesis negative 7 right parenthesis equals 7 end cell row blank blank blank row cell straight M subscript 33 end cell equals cell open vertical bar table row 1 0 row 2 2 end table close vertical bar equals 1 times 2 minus 0 times 2 equals 2 minus 0 equals 2 end cell row cell straight C subscript 33 end cell equals cell left parenthesis negative 1 right parenthesis to the power of 3 plus 3 end exponent times straight M subscript 33 end subscript equals left parenthesis negative 1 right parenthesis to the power of 6 times 2 equals 1 times 2 equals 2 end cell end table end style  

Sehingga kita peroleh matriks kofaktornya adalah

begin mathsize 14px style open parentheses table row 13 cell negative 9 end cell 8 row 9 8 cell negative 3 end cell row cell negative 6 end cell 7 2 end table close parentheses end style  

Jadi, adjoinnya adalah

begin mathsize 14px style open parentheses table row 13 cell negative 9 end cell 8 row 9 8 cell negative 3 end cell row cell negative 6 end cell 7 2 end table close parentheses to the power of T equals open parentheses table row 13 9 cell negative 6 end cell row cell negative 9 end cell 8 7 row 8 cell negative 3 end cell 2 end table close parentheses end style  

Selanjutnya, kita cari determinan matriks D  dengan metode Sarrus.

Kita peroleh

diagonal kanan = 1 ∙ 2 ∙ 5 + 0 ∙ (-1) ∙ (-1) + 3 ∙ 2 ∙ 3
                         = 10 + 0 + 18
                         = 28

diagonal kiri = 3 ∙ 2 ∙ (-1) + 1 ∙ (-1) ∙ 3 + 0 ∙ 2 ∙ 5
                    = - 6 - 3 + 0
                    = - 9

Sehingga determinannya adalah

determinan = diagonal kanan - diagonal kiri
                   = 28 - (-9)
                   = 37

Jadi, invers dari matriks D  adalah

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight D to the power of negative 1 end exponent end cell equals cell fraction numerator 1 over denominator vertical line straight D vertical line end fraction times adj blank straight D end cell row blank equals cell 1 over 37 open parentheses table row 13 9 cell negative 6 end cell row cell negative 9 end cell 8 7 row 8 cell negative 3 end cell 2 end table close parentheses end cell end table end style  

Dengan demikian, jawaban yang tepat adalah B.

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