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Pertanyaan

N i l ai d a r i x → 0 lim ​ sin 3 x sin 5 x ​ = ...

  1. 1

  2. 0

  3. -1

  4. 3 over 5

  5. 5 over 3

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A. Acfreelance

Master Teacher

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S i f a t space l i m i t space t r i g o n o m e t r i colon  limit as x rightwards arrow 0 of fraction numerator sin a x over denominator a end fraction equals limit as x rightwards arrow 0 of fraction numerator a over denominator sin a x end fraction equals 1  limit as x rightwards arrow 0 of fraction numerator sin 5 x over denominator sin 3 x end fraction equals limit as x rightwards arrow 0 of fraction numerator sin 5 x 3 x 5 x over denominator sin 3 x 5 x 3 x end fraction  space space space space space space space space space space space space space space space space space space equals open parentheses limit as x rightwards arrow 0 of fraction numerator sin 5 x over denominator 5 x end fraction close parentheses open parentheses limit as x rightwards arrow 0 of fraction numerator 3 x over denominator sin 3 x end fraction close parentheses open parentheses 5 over 3 close parentheses  space space space space space space space space space space space space space space space space space space equals 1.1. open parentheses 5 over 3 close parentheses  space space space space space space space space space space space space space space space space space space equals 5 over 3

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Nilai x → 3 π ​ lim ​ sin ( 3 x − π ) tan ( 3 x − π ) cos ( 2 x ) ​ adalah ...

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