Iklan

Pertanyaan

J ika f ( x ) = x 2 + 1 ​ d an ( f o g ) = x − 2 1 ​ x 2 − 4 x + 5 ​ maka g ( x − 3 ) a d a l ah ...

  1. fraction numerator 1 over denominator x minus 5 end fraction

  2. fraction numerator 1 over denominator x plus 1 end fraction

  3. fraction numerator 1 over denominator x minus 3 end fraction

  4. fraction numerator 1 over denominator negative x minus 3 end fraction

  5. fraction numerator 1 over denominator x plus 3 end fraction

Belajar bareng Champions

Brain Academy Champions

Hanya di Brain Academy

Habis dalam

01

:

18

:

19

:

18

Klaim

Iklan

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

left parenthesis f o g right parenthesis left parenthesis x right parenthesis equals f left parenthesis g left parenthesis x right parenthesis right parenthesis  left parenthesis f o g right parenthesis left parenthesis x right parenthesis equals fraction numerator 1 over denominator x minus 2 end fraction square root of x squared minus 4 x plus 5 end root  square root of open parentheses g left parenthesis x right parenthesis close parentheses squared plus 1 end root equals fraction numerator 1 over denominator x minus 2 end fraction square root of x squared minus 4 x plus 5 end root  open parentheses g left parenthesis x right parenthesis close parentheses squared plus 1 equals fraction numerator x squared minus 4 x plus 5 over denominator left parenthesis x minus 2 right parenthesis squared end fraction  open parentheses g left parenthesis x right parenthesis close parentheses squared equals fraction numerator x squared minus 4 x plus 5 over denominator left parenthesis x minus 2 right parenthesis squared end fraction minus 1  open parentheses g left parenthesis x right parenthesis close parentheses squared equals fraction numerator x squared minus 4 x plus 5 minus left parenthesis x minus 2 right parenthesis squared over denominator left parenthesis x minus 2 right parenthesis squared end fraction  open parentheses g left parenthesis x right parenthesis close parentheses squared equals fraction numerator x squared minus 4 x plus 5 minus left parenthesis x squared minus 4 x plus 4 right parenthesis over denominator left parenthesis x minus 2 right parenthesis squared end fraction  open parentheses g left parenthesis x right parenthesis close parentheses squared equals fraction numerator 1 over denominator left parenthesis x minus 2 right parenthesis squared end fraction  g left parenthesis x right parenthesis equals square root of fraction numerator 1 over denominator left parenthesis x minus 2 right parenthesis squared end fraction end root equals fraction numerator 1 over denominator x minus 2 end fraction  g left parenthesis x minus 3 right parenthesis equals fraction numerator 1 over denominator x minus 2 end fraction equals fraction numerator 1 over denominator left parenthesis x minus 3 right parenthesis minus 2 end fraction equals fraction numerator 1 over denominator x minus 5 end fraction

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

Naifa Ardelia

Pembahasan lengkap banget Mudah dimengerti

Wilda tri Ramadhani

Makasih ❤️

Iklan

Pertanyaan serupa

Diketahui fungsi f ( x ) = 1 + x 2 ​ dan ( f ∘ g ) ( x ) = x − 2 1 ​ x 2 − 4 x + 5 ​ . Rumus fungsi g ( x + 3 ) = ...

4

4.3

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia