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Pertanyaan

D ik e t ah u i a = 2 i + 2 j + 9 k d an b = 2 i − 2 j + k . P roye k s i v e k t or or t h o g o na l a p a d a b a d a l ah ...

  1. 3 i space minus space 3 j space plus space k

  2. 3 i space minus space 5 j space minus space 2 k

  3. 4 i space minus space 4 j space plus space 2 k

  4. 2 i space minus space 2 j space plus space k

  5. 5 i space plus space 5 j space plus space 5 k

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D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

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Pembahasan

p r o y e k s i space a with rightwards arrow on top space k e space b with rightwards arrow on top equals fraction numerator a with rightwards arrow on top bullet b with rightwards arrow on top over denominator open vertical bar b with rightwards arrow on top close vertical bar squared end fraction bullet b with rightwards arrow on top  equals fraction numerator open parentheses table row 2 row 2 row 9 end table close parentheses bullet open parentheses table row 2 row cell negative 2 end cell row 1 end table close parentheses over denominator square root of 2 squared plus open parentheses negative 2 close parentheses squared plus 1 squared end root squared end fraction bullet b with rightwards arrow on top  equals open parentheses fraction numerator 4 plus open parentheses negative 4 close parentheses plus 9 over denominator open parentheses square root of 4 plus 4 plus 1 end root close parentheses squared end fraction close parentheses bullet b with rightwards arrow on top  equals 9 over 9 open parentheses 2 i minus 2 j plus k close parentheses  equals 2 i minus 2 j plus k

Perdalam pemahamanmu bersama Master Teacher
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1

Muhamad Dika Fachri

Pembahasan lengkap banget Mudah dimengerti

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