Iklan

Pertanyaan

D ik e t ah u i a = 2 i + 2 j + 9 k d an b = 2 i − 2 j + k . P roye k s i v e k t or or t h o g o na l a p a d a b a d a l ah ...

  1. 3 i space minus space 3 j space plus space k

  2. 3 i space minus space 5 j space minus space 2 k

  3. 4 i space minus space 4 j space plus space 2 k

  4. 2 i space minus space 2 j space plus space k

  5. 5 i space plus space 5 j space plus space 5 k

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

10

:

24

:

47

Klaim

Iklan

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

p r o y e k s i space a with rightwards arrow on top space k e space b with rightwards arrow on top equals fraction numerator a with rightwards arrow on top bullet b with rightwards arrow on top over denominator open vertical bar b with rightwards arrow on top close vertical bar squared end fraction bullet b with rightwards arrow on top  equals fraction numerator open parentheses table row 2 row 2 row 9 end table close parentheses bullet open parentheses table row 2 row cell negative 2 end cell row 1 end table close parentheses over denominator square root of 2 squared plus open parentheses negative 2 close parentheses squared plus 1 squared end root squared end fraction bullet b with rightwards arrow on top  equals open parentheses fraction numerator 4 plus open parentheses negative 4 close parentheses plus 9 over denominator open parentheses square root of 4 plus 4 plus 1 end root close parentheses squared end fraction close parentheses bullet b with rightwards arrow on top  equals 9 over 9 open parentheses 2 i minus 2 j plus k close parentheses  equals 2 i minus 2 j plus k

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Muhamad Dika Fachri

Pembahasan lengkap banget Mudah dimengerti

Iklan

Pertanyaan serupa

Diketahui vektor a = ⎝ ⎛ ​ − 1 − 3 2 ​ ⎠ ⎞ ​ dan b = ⎝ ⎛ ​ − 2 6 1 ​ ⎠ ⎞ ​ . Vektor proyeksi ortogonal dari vektor b pada vektor a adalah ....

7

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia