Roboguru
SD

x→5lim​ x2−5x2x2−3x−35​= ...

Pertanyaan

begin mathsize 14px style limit as x rightwards arrow 5 of space fraction numerator 2 x squared minus 3 x minus 35 over denominator x squared minus 5 x end fraction equals space... end style 

E. Dwi

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

nilai begin mathsize 14px style limit as x rightwards arrow 5 of space fraction numerator 2 x squared minus 3 x minus 35 over denominator x squared minus 5 x end fraction end style adalah begin mathsize 14px style 17 over 5 end style

Pembahasan

Limit fungsi aljabar adalah menentukan nilai fungsi aljabar jika peubah fungsi tersebut mendekati nilai tertentu.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 5 of space fraction numerator 2 x squared minus 3 x minus 35 over denominator x squared minus 5 x end fraction end cell equals cell limit as x rightwards arrow 5 of space fraction numerator left parenthesis 2 x plus 7 right parenthesis left parenthesis x minus 5 right parenthesis over denominator x open parentheses x minus 5 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 5 of space fraction numerator left parenthesis 2 x plus 7 right parenthesis up diagonal strike left parenthesis x minus 5 right parenthesis end strike over denominator x up diagonal strike open parentheses x minus 5 close parentheses end strike end fraction end cell row blank equals cell limit as x rightwards arrow 5 of space fraction numerator 2 x plus 7 over denominator x end fraction end cell row blank equals cell fraction numerator 2 left parenthesis 5 right parenthesis plus 7 over denominator 5 end fraction end cell row blank equals cell fraction numerator 10 plus 7 over denominator 5 end fraction end cell row blank equals cell 17 over 5 end cell end table end style

Jadi, nilai begin mathsize 14px style limit as x rightwards arrow 5 of space fraction numerator 2 x squared minus 3 x minus 35 over denominator x squared minus 5 x end fraction end style adalah begin mathsize 14px style 17 over 5 end style

53

5.0 (3 rating)

Deswita Yuki

Bantu banget

Pertanyaan serupa

x→3lim​x−3x2−5x+6​=...

94

4.5

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia