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Pertanyaan

x → 3 lim ​ − 3 x 2 + 11 x − 6 x − 3 ​

 

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S. Amamah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Jawaban

 begin mathsize 14px style limit as x rightwards arrow 3 of space table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x minus 3 over denominator negative 3 x squared plus 11 x minus 6 end fraction end cell end table equals negative 7 end style  

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begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 3 of space fraction numerator x minus 3 over denominator negative 3 x squared plus 11 x minus 6 end fraction end cell equals cell limit as x rightwards arrow 3 of space fraction numerator x minus 3 over denominator left parenthesis negative 3 x plus 2 right parenthesis left parenthesis x minus 3 right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 3 of space fraction numerator 1 over denominator left parenthesis negative 3 x plus 2 right parenthesis end fraction end cell row blank equals cell fraction numerator 1 over denominator negative 3 left parenthesis 3 right parenthesis plus 2 end fraction end cell row blank equals cell fraction numerator 1 over denominator negative 7 end fraction end cell end table end style   

Jadi, begin mathsize 14px style limit as x rightwards arrow 3 of space table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x minus 3 over denominator negative 3 x squared plus 11 x minus 6 end fraction end cell end table equals negative 7 end style  

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