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Pertanyaan

1. Jika a = ⎝ ⎛ ​ 2 3 1 ​ ⎠ ⎞ ​ , b = ⎝ ⎛ ​ 5 − 2 − 4 ​ ⎠ ⎞ ​ , dan c = ⎝ ⎛ ​ 10 − 13 19 ​ ⎠ ⎞ ​ , buktikan bahwa ketiga vektor tersebut saling tegak lurus.

1. Jika , buktikan bahwa ketiga vektor tersebut saling tegak lurus.space  

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R. Diah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

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terbukti bahwa vektor saling tegak lurus.

terbukti bahwa vektor a with rightwards arrow on top comma space b with rightwards arrow on top comma space dan space c with rightwards arrow on top saling tegak lurus.space 

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Pembahasan

Vektor dikatakan saling tegak lurus jika Perhatikan penghitungan berikut! Jadi, terbukti bahwa vektor saling tegak lurus.

Vektor a with rightwards arrow on top comma space b with rightwards arrow on top comma space dan space c with rightwards arrow on top dikatakan saling tegak lurus jika

 a with rightwards arrow on top times b with rightwards arrow on top equals 0 a with rightwards arrow on top times c with rightwards arrow on top equals 0 b with rightwards arrow on top times c with rightwards arrow on top equals 0 

Perhatikan penghitungan berikut!

 a with rightwards arrow on top times b with rightwards arrow on top equals open parentheses table row 2 row 3 row 1 end table close parentheses times open parentheses table row 5 row cell negative 2 end cell row cell negative 4 end cell end table close parentheses equals 2 open parentheses 5 close parentheses plus 3 open parentheses negative 2 close parentheses plus 1 open parentheses negative 4 close parentheses equals 0 a with rightwards arrow on top times c with rightwards arrow on top equals open parentheses table row 2 row 3 row 1 end table close parentheses times open parentheses table row 10 row cell negative 13 end cell row 19 end table close parentheses equals 2 open parentheses 10 close parentheses plus 3 open parentheses negative 13 close parentheses plus 1 open parentheses 19 close parentheses equals 0 b with rightwards arrow on top times c with rightwards arrow on top equals open parentheses table row 5 row cell negative 2 end cell row cell negative 4 end cell end table close parentheses times open parentheses table row 10 row cell negative 13 end cell row 19 end table close parentheses equals 5 open parentheses 10 close parentheses plus open parentheses negative 2 close parentheses open parentheses negative 13 close parentheses plus open parentheses negative 4 close parentheses open parentheses 19 close parentheses equals 0  

Jadi, terbukti bahwa vektor a with rightwards arrow on top comma space b with rightwards arrow on top comma space dan space c with rightwards arrow on top saling tegak lurus.space 

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