Pertanyaan

A ka r − aka r p ers amaan x 2 + ( a − 1 ) x + 2 = 0 a d l aah α d an β . J ika α = 2 β d an a > 0 maka ni l ai a = ...

$A ka r - aka r p ers amaan x^{2} + (a - 1) x + 2 = 0 a d l aah α d an β . J ika α = 2 β d an a > 0 maka ni l ai a = ...$

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Klaim

F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Pembahasan

$P e r s a m a a n space x squared plus left parenthesis a minus 1 right parenthesis x plus 2 equals 0 space M e m i l i k i space a k a r minus a k a r space alpha space d a n space beta comma m a k a space p e n j u m l a h a n space d a n space p e r k a l i a n space a k a r minus a k a r n y a space a d a l a h alpha plus beta equals negative fraction numerator a minus 1 over denominator 1 end fraction equals negative a plus 1 alpha beta equals 2 over 1 equals 2 S e m e n t a r a space alpha equals 2 beta comma space s e h i n g g a alpha beta equals 2 rightwards arrow 2 beta squared equals 2 rightwards arrow beta squared equals 1 rightwards arrow beta equals plus-or-minus 1 J i k a space beta equals 1 comma space m a k a space alpha.1 equals 2 rightwards arrow space alpha equals 2 S e h i n g g a space alpha plus beta equals negative a plus 1 rightwards arrow space 2 plus 1 equals negative a plus 1 rightwards arrow a space equals space 1 minus 3 space equals space minus 2 J i k a space beta equals negative 1 comma space m a k a space alpha left parenthesis negative 1 right parenthesis equals 2 rightwards arrow space alpha equals negative 2 S e h i n g g a space alpha plus beta equals negative a plus 1 rightwards arrow negative space 2 minus 1 equals negative a plus 1 rightwards arrow a space equals 1 plus 3 space equals space 4$