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Pertanyaan

begin mathsize 14px style lim subscript straight x rightwards arrow negative 1 end subscript fraction numerator cube root of straight x squared end root plus 2 cube root of straight x plus 1 over denominator open parentheses straight x plus 1 close parentheses squared end fraction equals end style ...

  1. begin mathsize 14px style negative 1 over 9 end style 

  2. begin mathsize 14px style negative 1 third end style 

  3. 1

  4. begin mathsize 14px style 1 third end style 

  5. begin mathsize 14px style 1 over 9 end style 

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

Perhatikan bahwa jika dilakukan substitusi = -1, maka didapatkan hasil undefined .
Sehingga perlu dicari cara lain untuk mencari nilai limitnya.

Misalkan begin mathsize 14px style straight x equals straight y cubed end style 
Maka untuk begin mathsize 14px style straight x rightwards arrow negative 1 end style , maka didapat bahwa begin mathsize 14px style straight y rightwards arrow negative 1 end style .
Sehingga

begin mathsize 14px style limit as x rightwards arrow negative 1 of fraction numerator cube root of x squared end root plus 2 cube root of x plus 1 over denominator open parentheses x plus 1 close parentheses squared end fraction equals limit as y rightwards arrow negative 1 of fraction numerator cube root of open parentheses y cubed close parentheses squared end root plus 2 cube root of y cubed end root plus 1 over denominator open parentheses y cubed plus 1 close parentheses squared end fraction equals limit as y rightwards arrow negative 1 of fraction numerator y squared plus 2 y plus 1 over denominator open parentheses y cubed plus 1 close parentheses squared end fraction equals limit as y rightwards arrow negative 1 of open parentheses y plus 1 close parentheses squared over open parentheses open parentheses y plus 1 close parentheses open parentheses y squared minus y plus 1 close parentheses close parentheses squared equals limit as y rightwards arrow negative 1 of fraction numerator open parentheses y plus 1 close parentheses squared over denominator open parentheses y plus 1 close parentheses squared open parentheses y squared minus y plus 1 close parentheses squared end fraction equals limit as y rightwards arrow negative 1 of 1 over open parentheses y squared minus y plus 1 close parentheses squared equals 1 over open parentheses open parentheses negative 1 close parentheses squared minus open parentheses negative 1 close parentheses plus 1 close parentheses squared equals 1 over open parentheses 1 plus 1 plus 1 close parentheses squared equals 1 over open parentheses 3 close parentheses squared equals 1 over 9 end style 

50

5.0 (1 rating)

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limx→1​1−3x​1−x​​= ...

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