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x → ∞ lim x 4 − x 2 + 3 x + 5 x 3 − 3 x 2 + 4 x + 1 = ....

$x \to \infty lim \frac{x ^{3} - 3 x ^{2} + 4 x + 1}{x ^{4} - x ^{2} + 3 x + 5} =$ ....

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nilai dari .

nilai dari $begin mathsize 14px style limit as x rightwards arrow infinity of space fraction numerator x cubed minus 3 x squared plus 4 x plus 1 over denominator x to the power of 4 minus x squared plus 3 x plus 5 end fraction equals 0 end style$ .

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$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow infinity of space fraction numerator x cubed minus 3 x squared plus 4 x plus 1 over denominator x to the power of 4 minus x squared plus 3 x plus 5 end fraction end cell equals cell limit as x rightwards arrow infinity of space fraction numerator x cubed minus 3 x squared plus 4 x plus 1 over denominator x to the power of 4 minus x squared plus 3 x plus 5 end fraction cross times fraction numerator begin display style 1 over x to the power of 4 end style over denominator begin display style 1 over x to the power of 4 end style end fraction end cell row blank equals cell limit as x rightwards arrow infinity of space fraction numerator begin display style 1 over x end style minus begin display style 3 over x squared end style plus begin display style 4 over x cubed end style plus begin display style fraction numerator 1 over denominator x 4 end fraction end style over denominator 1 minus begin display style 1 over x squared end style plus begin display style 3 over x cubed end style plus begin display style 5 over x to the power of 4 end style end fraction end cell row blank equals cell fraction numerator 0 minus 0 plus 0 plus 0 over denominator 1 minus 0 plus 0 plus 0 end fraction end cell row blank equals cell 0 over 1 end cell row blank equals 0 end table$

Jadi, nilai dari $begin mathsize 14px style limit as x rightwards arrow infinity of space fraction numerator x cubed minus 3 x squared plus 4 x plus 1 over denominator x to the power of 4 minus x squared plus 3 x plus 5 end fraction equals 0 end style$ .

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