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Vektor satuan dari  adalah ....

Vektor satuan dari a with bar on top equals open parentheses table row 7 row cell negative 14 end cell end table close parentheses adalah ....

  1. open parentheses 1 over 7 square root of 7 comma 2 over 7 square root of 7 close parentheses 

  2. open parentheses 1 over 7 square root of 7 comma negative 2 over 7 square root of 7 close parentheses 

  3. open parentheses 1 fifth square root of 5 comma negative 1 fifth square root of 5 close parentheses 

  4. open parentheses 1 fifth square root of 5 comma 2 over 5 square root of 5 close parentheses 

  5. open parentheses 1 fifth square root of 5 comma negative 2 over 5 square root of 5 close parentheses 

Jawaban:

Vektor satuan dari a with bar on top didapatkan:

table attributes columnalign right center left columnspacing 0px end attributes row cell Vektor space satuan space a with rightwards arrow on top end cell equals cell fraction numerator a with rightwards arrow on top over denominator open vertical bar a with rightwards arrow on top close vertical bar end fraction end cell row blank equals cell fraction numerator 1 over denominator square root of 7 squared plus open parentheses negative 14 close parentheses squared end root end fraction open parentheses table row 7 row cell negative 14 end cell end table close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 49 plus 196 end root end fraction open parentheses table row 7 row cell negative 14 end cell end table close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 245 end fraction open parentheses table row 7 row cell negative 14 end cell end table close parentheses end cell row blank equals cell fraction numerator 1 over denominator 7 square root of 5 end fraction open parentheses table row 7 row cell negative 14 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell 1 fifth square root of 5 end cell row cell negative 2 over 5 square root of 5 end cell end table close parentheses end cell end table  

Dengan demikian, vektor satuan dari a with bar on top equals open parentheses table row 7 row cell negative 14 end cell end table close parentheses adalah open parentheses 1 fifth square root of 5 comma negative 2 over 5 square root of 5 close parentheses.

Jadi, jawaban yang benar adalah E.

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