Iklan

Pertanyaan

Vektor satuan a = ( 5 , 1 ) adalah ....

Vektor satuan  adalah ....

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

22

:

52

:

41

Klaim

Iklan

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

diperoleh vektor satuannya adalah .

diperoleh vektor satuannya adalah a equals open parentheses 5 over 26 square root of 26 comma space 1 over 26 square root of 26 close parentheses.

Pembahasan

Pembahasan
lock

Gunakan vektor satuan dua dimensi, misal vektor . Perhatikan perhitungan berikut. Jadi, diperoleh vektor satuannya adalah .

Gunakan vektor satuan dua dimensi, misal vektor a open parentheses x comma space y close parentheses.

table attributes columnalign right center left columnspacing 2px end attributes row a equals cell fraction numerator 1 over denominator open vertical bar a with rightwards arrow on top close vertical bar end fraction cross times a with rightwards arrow on top end cell row cell open vertical bar a with rightwards arrow on top close vertical bar end cell equals cell square root of x squared plus y squared end root end cell end table

Perhatikan perhitungan berikut.

table attributes columnalign right center left columnspacing 2px end attributes row a equals cell fraction numerator 1 over denominator open vertical bar a with rightwards arrow on top close vertical bar end fraction cross times a with rightwards arrow on top end cell row blank equals cell fraction numerator 1 over denominator square root of 5 squared plus 1 squared end root end fraction cross times open parentheses 5 comma space 1 close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 25 plus 1 end root end fraction cross times open parentheses 5 comma space 1 close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 26 end fraction cross times open parentheses 5 comma space 1 close parentheses end cell row blank equals cell open parentheses fraction numerator 5 over denominator square root of 26 end fraction comma space fraction numerator 1 over denominator square root of 26 end fraction close parentheses end cell row a equals cell open parentheses 5 over 26 square root of 26 comma space 1 over 26 square root of 26 close parentheses end cell end table

Jadi, diperoleh vektor satuannya adalah a equals open parentheses 5 over 26 square root of 26 comma space 1 over 26 square root of 26 close parentheses.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

Iklan

Pertanyaan serupa

Misalkan P = 8 i + 15 j ​ . a. Carilah ∣ ∣ ​ P ∣ ∣ ​ b. Tunjukkan bahwa ∣ ∣ ​ P ∣ ∣ ​ P ​ adalah vektor satuan.

7

4.5

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia