Pertanyaan

Turunan pertama dari adalah ....

Turunan pertama dari $begin mathsize 14px style straight f open parentheses straight x close parentheses equals fraction numerator straight x squared plus straight x minus 1 over denominator 3 straight x squared plus straight x plus 5 end fraction blank end style$ adalah ....

$begin mathsize 14px style fraction numerator negative 2 straight x squared plus 16 straight x plus 6 over denominator open parentheses 3 straight x squared plus straight x plus 5 close parentheses squared end fraction end style$
$begin mathsize 14px style fraction numerator 2 straight x squared plus 16 straight x minus 6 over denominator open parentheses 3 straight x squared plus straight x plus 5 close parentheses squared end fraction end style$
$begin mathsize 14px style fraction numerator straight x squared plus 16 straight x minus 6 over denominator open parentheses 3 straight x squared plus straight x plus 5 close parentheses squared end fraction end style$
$begin mathsize 14px style fraction numerator negative 2 straight x squared plus 16 straight x minus 6 over denominator open parentheses 3 straight x squared plus straight x plus 5 close parentheses squared end fraction end style$
$begin mathsize 14px style fraction numerator negative 2 straight x squared minus 16 straight x minus 6 over denominator open parentheses 3 straight x squared plus straight x plus 5 close parentheses squared end fraction end style$

H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

Ingat kembali turunan pertama fungsi dalam irasional berikut ini adalah Sehingga pada fungsi irasional berikut ini Kita misalkan: Maka diperoleh, Sehingga turunan pertama fungsi tersebut adalah

Ingat kembali turunan pertama fungsi dalam irasional berikut ini

adalah

Sehingga pada fungsi irasional berikut ini

$begin mathsize 14px style straight f open parentheses straight x close parentheses equals fraction numerator straight x squared plus straight x minus 1 over denominator 3 straight x squared plus straight x plus 5 end fraction end style$

Kita misalkan:

Maka diperoleh,

Sehingga turunan pertama fungsi tersebut adalah

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight f to the power of straight apostrophe open parentheses straight x close parentheses end cell equals cell fraction numerator open parentheses 2 straight x plus 1 close parentheses open parentheses 3 straight x squared plus straight x plus 5 blank close parentheses minus open parentheses straight x squared plus straight x minus 1 close parentheses open parentheses 6 straight x plus 1 close parentheses over denominator open parentheses 3 straight x squared plus straight x plus 5 close parentheses squared end fraction end cell row blank equals cell fraction numerator open parentheses 6 straight x cubed plus 5 straight x squared plus 11 straight x plus 5 close parentheses minus open parentheses 6 straight x cubed plus 7 straight x squared minus 5 straight x minus 1 close parentheses over denominator open parentheses 3 straight x squared plus straight x plus 5 close parentheses squared end fraction end cell row blank equals cell fraction numerator negative 2 straight x squared plus 16 straight x plus 6 over denominator open parentheses 3 straight x squared plus straight x plus 5 close parentheses squared end fraction end cell end table end style$