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Turunan pertama dari fungsi adalah ….

Turunan pertama dari fungsi begin mathsize 14px style straight f open parentheses straight x close parentheses equals open parentheses straight x cubed minus 3 straight x close parentheses open parentheses 1 plus 5 over straight x close parentheses end style adalah ….

  1. begin mathsize 14px style 3 straight x squared minus 10 straight x minus 3 end style

  2. begin mathsize 14px style 3 straight x squared plus 10 straight x minus 3 end style

  3. begin mathsize 14px style 3 straight x squared plus 10 straight x plus 3 end style

  4. begin mathsize 14px style 3 straight x squared plus 10 over straight x minus 3 end style

  5. begin mathsize 14px style 3 straight x squared minus 10 over straight x plus 3 end style

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M. Ridho

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.

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Pembahasan

Misalkan: Sehingga diperoleh, Maka, Dengan demikian, turunan pertama dari fungsi tersebut adalah . Jadi, jawaban yang tepat adalah B.

begin mathsize 14px style straight f open parentheses straight x close parentheses equals stack stack open parentheses straight x cubed minus 3 straight x close parentheses with underbrace below with straight u open parentheses straight x close parentheses below stack stack open parentheses 1 plus 5 over straight x close parentheses with underbrace below with straight v open parentheses straight x close parentheses below end style 

Misalkan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight u open parentheses straight x close parentheses end cell equals cell straight x cubed minus 3 straight x end cell row cell straight v open parentheses straight x close parentheses end cell equals cell 1 plus 5 over straight x end cell end table end style 

Sehingga diperoleh,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight u to the power of straight apostrophe open parentheses straight x close parentheses end cell equals cell 3 straight x squared minus 3 end cell row cell straight v to the power of straight apostrophe open parentheses straight x close parentheses end cell equals cell negative 5 over straight x squared end cell end table end style 

Maka,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight f to the power of straight apostrophe open parentheses straight x close parentheses end cell equals cell straight u to the power of straight apostrophe open parentheses straight x close parentheses blank straight v open parentheses straight x close parentheses plus straight u open parentheses straight x close parentheses blank straight v to the power of straight apostrophe open parentheses straight x close parentheses end cell row cell straight f to the power of straight apostrophe open parentheses straight x close parentheses end cell equals cell open parentheses 3 straight x squared minus 3 close parentheses open parentheses 1 plus 5 over straight x close parentheses plus open parentheses straight x cubed minus 3 straight x close parentheses open parentheses negative 5 over straight x squared close parentheses end cell row blank equals cell 3 straight x squared plus 15 straight x minus 3 minus 15 over straight x minus 5 straight x plus 15 over straight x end cell row blank equals cell 3 straight x squared plus 10 straight x minus 3 end cell end table end style 

Dengan demikian, turunan pertama dari fungsi tersebut adalah begin mathsize 14px style straight f to the power of straight apostrophe open parentheses straight x close parentheses equals 3 straight x squared plus 10 straight x minus 3 end style.

Jadi, jawaban yang tepat adalah B.

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