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Tentukan pH larutan penyangga berikut : 400 ml larutan 0,1 M + 200 ml larutan 0,1 M

Tentukan pH larutan penyangga berikut :

400 ml larutan begin mathsize 14px style H C N end style 0,1 M + 200 ml larutan begin mathsize 14px style Na C N end style 0,1 M

begin mathsize 14px style open parentheses K subscript a space H C N equals 4 cross times 10 to the power of negative sign 5 end exponent close parentheses end style

Jawaban:

begin mathsize 14px style H C N and Na C N end style merupakan larutan penyangga bersifat asam. Rumus mencari pH larutan penyangga :

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals K subscript a open parentheses M cross times V close parentheses subscript HCN over open parentheses M cross times V close parentheses subscript NaCN space space space space space space space space equals 4.10 to the power of negative sign 5 end exponent fraction numerator 0 comma 1 cross times 400 over denominator 0 comma 1 cross times 200 end fraction space space space space space space space space equals 8.10 to the power of negative sign 5 end exponent pH equals minus sign log space open square brackets H to the power of plus sign close square brackets space space space space space equals minus sign log space 8.10 to the power of negative sign 5 end exponent space space space space space equals 5 minus sign log space 8 end style

Jadi, pH larutan penyangga tersebut adalah 5 - log 8.

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