Pertanyaan

Tentukan nilai x pada segitiga siku-siku

Tentukan nilai $x$ pada segitiga siku-siku

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Jawaban terverifikasi

Jawaban

nilai .

nilai

x equals 1 third open parentheses 16 square root of 3 minus 6 close parentheses

Pembahasan

Ingat nilai , sehingga Jadi nilai .

Ingat nilai $cos space alpha equals fraction numerator sisi space samping space sudut over denominator sisi space miring space sudut end fraction$ , sehingga

$table attributes columnalign right center left columnspacing 0px end attributes row cell cos 30 to the power of o end cell equals cell fraction numerator 8 over denominator x plus 2 end fraction end cell row cell 1 half square root of 3 end cell equals cell fraction numerator 8 over denominator x plus 2 end fraction end cell row cell square root of 3 open parentheses x plus 2 close parentheses end cell equals 16 row cell space space space space space space space space space x plus 2 end cell equals cell fraction numerator 16 over denominator square root of 3 end fraction end cell row cell space space space space space space space space space x plus 2 end cell equals cell 16 over 3 square root of 3 end cell row cell space space space space space space space space space space space space space space space x end cell equals cell 16 over 3 square root of 3 minus 2 end cell row cell space space space space space space space space space space space space space space space x end cell equals cell 1 third open parentheses 16 square root of 3 minus 6 close parentheses end cell row blank blank blank row blank blank blank end table$

Jadi nilai x equals 1 third open parentheses 16 square root of 3 minus 6 close parentheses .