Iklan

Pertanyaan

Tentukan nilai mutlak dari ∣ ∣ ​ 1 2 2 1 ​ − 2 4 2 3 ​ ∣ ∣ ​

Tentukan nilai mutlak dari space space 

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

20

:

28

:

39

Klaim

Iklan

M. Claudia

Master Teacher

Mahasiswa/Alumni Universitas Nusa Cendana Kupang

Jawaban terverifikasi

Jawaban

nilai mutlak dari adalah .

 nilai mutlak dari open vertical bar 12 to the power of 1 half end exponent minus 24 to the power of 3 over 2 end exponent close vertical bar adalah 48 square root of 6 minus 2 square root of 3.space space 

Pembahasan

Ingat, Definisi nilai mutlak Sifat Bilangan Berpangkat Diperoleh sebagai berikut Sesuai definisi nilai mutlak karena , maka Dengan demikian,nilai mutlak dari adalah .

Ingat,

Definisi nilai mutlak

open vertical bar a close vertical bar equals open curly brackets table attributes columnalign left columnspacing 1.4ex end attributes row a cell jika space a greater or equal than 0 end cell row cell negative a end cell cell jika space a less than 0 end cell end table close

Sifat Bilangan Berpangkat

a to the power of m over n end exponent equals n-th root of a to the power of m end root

Diperoleh sebagai berikut

open vertical bar 12 to the power of 1 half end exponent minus 24 to the power of 3 over 2 end exponent close vertical bar
12 to the power of 1 half end exponent equals square root of 12 to the power of 1 end root equals square root of 12 equals square root of 4 cross times 3 end root equals 2 square root of 3 24 to the power of 3 over 2 end exponent equals square root of 24 cubed end root equals square root of 24 cross times 24 cross times 24 end root equals 24 square root of 24 equals 24 square root of 4 cross times 6 end root equals 48 square root of 6  open vertical bar 12 to the power of 1 half end exponent minus 24 to the power of 3 over 2 end exponent close vertical bar equals open vertical bar 2 square root of 3 minus 48 square root of 6 close vertical bar
 

Sesuai definisi nilai mutlak karena 2 square root of 3 minus 48 square root of 6 less than 0, maka

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar 12 to the power of 1 half end exponent minus 24 to the power of 3 over 2 end exponent close vertical bar end cell equals cell open vertical bar 2 square root of 3 minus 48 square root of 6 close vertical bar end cell row blank equals cell negative open parentheses 2 square root of 3 minus 48 square root of 6 close parentheses end cell row blank equals cell 48 square root of 6 minus 2 square root of 3 end cell end table

Dengan demikian, nilai mutlak dari open vertical bar 12 to the power of 1 half end exponent minus 24 to the power of 3 over 2 end exponent close vertical bar adalah 48 square root of 6 minus 2 square root of 3.space space 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

65

Syalom Amos Farel Sitanggang

Makasih Kak ❤️

Iklan

Pertanyaan serupa

Agar persamaan ∣ 2 x − 5 ∣ = 11 maka nilai x haruslah ...

3

4.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia