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Tentukan nilai limit berikut. c. x→52​lim​(5x−2)210x−5​

Pertanyaan

Tentukan nilai limit berikut.

c. begin mathsize 14px style limit as x rightwards arrow 2 over 5 of fraction numerator 10 x minus 5 over denominator open parentheses 5 x minus 2 close parentheses squared end fraction end style 

P. Tessalonika

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

Jawaban

nilai dari limit as x rightwards arrow 2 over 5 of fraction numerator 10 x minus 5 over denominator open parentheses 5 x minus 2 close parentheses squared end fraction equals negative infinity.

Pembahasan

Untuk menyelesaikan soal tersebut kita substitusi nilai x equals 2 over 5 pada limit fungsi tersebut diperoleh:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 2 over 5 of fraction numerator 10 x minus 5 over denominator blank end fraction end cell equals cell fraction numerator 10 open parentheses begin display style 2 over 5 end style close parentheses minus 5 over denominator open parentheses 5 open parentheses begin display style 2 over 5 end style close parentheses minus 2 close parentheses squared end fraction end cell row blank equals cell fraction numerator 4 minus 5 over denominator open parentheses 2 minus 2 close parentheses squared end fraction end cell row blank equals cell fraction numerator negative 1 over denominator 0 squared end fraction end cell row blank equals cell negative infinity end cell end table end style 

Dengan demikian, nilai dari limit as x rightwards arrow 2 over 5 of fraction numerator 10 x minus 5 over denominator open parentheses 5 x minus 2 close parentheses squared end fraction equals negative infinity.

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