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x → 1 lim ​ 2 x 2 + x x 2 + 4 x ​ = ...

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Y. Herlanda

Master Teacher

Mahasiswa/Alumni STKIP PGRI Jombang

Jawaban terverifikasi

Jawaban

nilai dari .

nilai dari table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 1 of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x squared plus 4 x over denominator 2 x squared plus x end fraction end cell end table equals 5 over 3.

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Pembahasan

Jadi, nilai dari .

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of fraction numerator x squared plus 4 x over denominator 2 x squared plus x end fraction end cell equals cell limit as x rightwards arrow 1 of fraction numerator x open parentheses x plus 4 close parentheses over denominator x open parentheses 2 x plus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator open parentheses x plus 4 close parentheses over denominator open parentheses 2 x plus 1 close parentheses end fraction end cell row blank equals cell fraction numerator 1 plus 4 over denominator 2 open parentheses 1 close parentheses plus 1 end fraction end cell row blank equals cell 5 over 3 end cell end table

Jadi, nilai dari table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 1 of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x squared plus 4 x over denominator 2 x squared plus x end fraction end cell end table equals 5 over 3.

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Dengan mensubstitusi nilai-nilai yang didekati oleh x , tentukan nilai limit fungsi tersebut. i. x → 2 lim ​ x 2 − 1 x 4 − 1 ​

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