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Tentukan nilai a dan b yang memenuhi kesamaaan. .

Tentukan  nilai  dan  yang memenuhi kesamaaan .

 size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 5 below size 14px space fraction numerator size 14px x to the power of size 14px 2 size 14px plus size 14px a size 14px x size 14px plus size 14px b over denominator size 14px 2 size 14px x to the power of size 14px 2 size 14px plus size 14px 7 size 14px x size 14px minus size 14px 15 end fraction size 14px equals size 14px 8 over size 14px 13.    

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I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Jawaban

nilaia = 18dan b = 65

nilai a = 18 dan b = 65

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Pembahasan

bentuk limit tak tentu , maka nilai dari pembilang haruslah 0, maka: Penyelesaiannya pada soal limit ini adalah , kerena bentuk limit tak tentu maka kita dapat menggunakan dalil L'Hopital, maka: Substitusi ke persamaan (1), maka: Jadi nilaia = 18dan b = 65

bentuk limit tak tentu begin mathsize 14px style 0 over 0 end style, maka nilai dari pembilang haruslah 0, maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell size 14px x to the power of size 14px 2 size 14px plus size 14px a size 14px x size 14px plus size 14px b end cell size 14px equals cell size 14px 0 size 14px space end cell row cell size 14px left parenthesis size 14px minus size 14px 5 size 14px right parenthesis to the power of size 14px 2 size 14px plus size 14px a size 14px left parenthesis size 14px minus size 14px 5 size 14px right parenthesis size 14px plus size 14px b end cell size 14px equals size 14px 0 row cell size 14px 25 size 14px minus size 14px 5 size 14px a size 14px plus size 14px b end cell size 14px equals size 14px 0 row cell size 14px minus size 14px 5 size 14px a size 14px plus size 14px b end cell size 14px equals cell size 14px minus size 14px 25 size 14px space size 14px space size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px. size 14px left parenthesis size 14px 1 size 14px right parenthesis end cell end table 

Penyelesaiannya pada soal limit ini adalah begin mathsize 14px style 8 over 13 end style, kerena bentuk limit tak tentu begin mathsize 14px style 0 over 0 end stylemaka kita dapat menggunakan dalil L'Hopital, maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 5 below size 14px space fraction numerator size 14px x to the power of size 14px 2 size 14px plus size 14px a size 14px x size 14px plus size 14px b over denominator size 14px 2 size 14px x to the power of size 14px 2 size 14px plus size 14px 7 size 14px x size 14px minus size 14px 15 end fraction end cell size 14px equals cell size 14px 8 over size 14px 13 end cell row cell size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 5 below size 14px space fraction numerator size 14px x to the power of size 14px 2 size 14px plus size 14px a size 14px x size 14px plus size 14px b over denominator size 14px 4 size 14px x size 14px plus size 14px 7 end fraction end cell size 14px equals cell size 14px 8 over size 14px 13 end cell row cell size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 5 below fraction numerator size 14px 2 size 14px x size 14px plus size 14px a over denominator size 14px 4 size 14px x size 14px plus size 14px 7 end fraction end cell size 14px equals cell size 14px 8 over size 14px 13 end cell row cell fraction numerator size 14px 2 size 14px left parenthesis size 14px minus size 14px 5 size 14px right parenthesis size 14px plus size 14px a over denominator size 14px 4 size 14px left parenthesis size 14px minus size 14px 5 size 14px right parenthesis size 14px plus size 14px 7 end fraction end cell size 14px equals cell size 14px 8 over size 14px 13 end cell row cell fraction numerator size 14px minus size 14px 10 size 14px plus size 14px a over denominator size 14px minus size 14px 20 size 14px plus size 14px 7 end fraction end cell size 14px equals cell size 14px 8 over size 14px 13 end cell row cell size 14px 13 size 14px left parenthesis size 14px minus size 14px 10 size 14px plus size 14px a size 14px right parenthesis end cell size 14px equals cell size 14px 8 size 14px cross times size 14px left parenthesis size 14px minus size 14px 13 size 14px right parenthesis end cell row cell size 14px minus size 14px 130 size 14px plus size 14px 13 size 14px a end cell size 14px equals size 14px 104 row size 14px a size 14px equals size 14px 18 end table 

Substitusi begin mathsize 14px style a equals 18 end style ke persamaan (1), maka:

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell negative 5 a plus b end cell equals cell negative 25 end cell row cell negative 5 left parenthesis 18 right parenthesis plus b end cell equals cell negative 25 end cell row cell negative 90 plus b end cell equals cell negative 25 end cell row b equals cell negative 25 plus 90 end cell row b equals 65 end table end style 

Jadi nilai a = 18 dan b = 65

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Devachelseaagustina

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Endy 321

Tidak sesuai Jawaban tidak sesuai

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