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Tentukan luas permukaan dan volume dari bangun kerucut berikut.

Tentukan luas permukaan dan volume dari bangun kerucut berikut. 

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D. Entry

Master Teacher

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Pembahasan

Pembahasan
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a. Perhatikan Jadi, tinggi kerucut adalah . Jadi, luas permukaan kerucut tersebut adalah . b. Perhatikan Jadi, jari-jari kerucut adalah . Jadi, luas permukaan kerucut tersebut adalah . c. Perhatikan Jadi, volumekerucut tersebut adalah .

a. Perhatikan

 table attributes columnalign right center left columnspacing 0px end attributes row V equals cell 1 third times straight pi times r squared times t end cell row cell 300 straight pi end cell equals cell 1 third times straight pi times 10 squared times straight t end cell row 900 equals cell 100 πt end cell row 9 equals straight t end table

Jadi, tinggi kerucut adalah 9 space straight m.

table attributes columnalign right center left columnspacing 0px end attributes row s equals cell square root of 10 squared plus 9 squared end root end cell row s equals cell square root of 100 plus 81 end root end cell row s equals cell square root of 181 straight m end cell row cell L subscript p end cell equals cell straight pi times r italic left parenthesis r italic plus s italic right parenthesis end cell row cell L subscript p end cell equals cell straight pi times 10 open parentheses 10 plus square root of 181 close parentheses space end cell row cell straight L subscript straight p end cell equals cell 10 straight pi open parentheses 10 plus square root of 181 close parentheses space straight m squared end cell row blank blank blank end table 

Jadi, luas permukaan kerucut tersebut adalah 10 straight pi table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses 10 plus square root of 181 close parentheses end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight m end table squared.

b. Perhatikan 

table attributes columnalign right center left columnspacing 0px end attributes row V equals cell 1 third times straight pi times r squared times t end cell row cell 120 straight pi end cell equals cell 1 third times straight pi times r squared times 10 end cell row cell 360 straight pi end cell equals cell 10 pi r squared end cell row 6 equals r end table

Jadi, jari-jari kerucut adalah 6 space straight m

table attributes columnalign right center left columnspacing 0px end attributes row s equals cell square root of 10 squared plus 6 squared end root end cell row s equals cell square root of 100 plus 36 end root end cell row s equals cell square root of 136 straight m end cell row cell L subscript p end cell equals cell straight pi times r italic left parenthesis r italic plus s italic right parenthesis end cell row cell L subscript p end cell equals cell straight pi times 6 open parentheses 6 plus square root of 136 close parentheses space end cell row cell straight L subscript straight p end cell equals cell 6 straight pi open parentheses 6 plus square root of 136 close parentheses space straight m squared end cell row blank blank blank end table 

Jadi, luas permukaan kerucut tersebut adalah 6 straight pi table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses 6 plus square root of 136 close parentheses end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell straight m squared end cell end table.

c. Perhatikan 

table attributes columnalign right center left columnspacing 0px end attributes row L equals cell straight pi times r open parentheses r plus s close parentheses end cell row cell 180 straight pi end cell equals cell straight pi times 8 open parentheses 8 plus straight s close parentheses end cell row cell 180 straight pi end cell equals cell 64 straight pi plus 8 πs end cell row cell 116 straight pi end cell equals cell 8 πs end cell row cell 14.5 end cell equals straight s end table

table attributes columnalign right center left columnspacing 0px end attributes row t equals cell square root of 14 comma 5 squared minus 8 squared end root end cell row t equals cell square root of 210.25 minus 64 end root end cell row t equals cell square root of 146 comma 25 end root end cell row blank blank blank row V equals cell 1 third times straight pi times r to the power of italic 2 italic times t end cell row straight V equals cell 1 third times straight pi times 8 to the power of italic 2 italic times square root of 146.25 end root end cell row straight V equals cell 64 over 3 straight pi square root of 146.25 end root space cm cubed end cell end table  

Jadi, volume kerucut tersebut adalah 64 over 3 straight pi square root of 146.25 end root space cm cubed

 

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