Tentukan himpunan penyelesaian dari setiap pertidaksamaan nilai mutlak di bawah ini. d. ∣∣​x2−5∣∣​≥4

Pertanyaan

Tentukan himpunan penyelesaian dari setiap pertidaksamaan nilai mutlak di bawah ini.

d. open vertical bar x squared minus 5 close vertical bar greater or equal than 4 

I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Jawaban

himpunan penyelesaian dari pertidaksamaan open vertical bar x squared minus 5 close vertical bar greater or equal than 4 adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open curly brackets right enclose x x less or equal than negative 3 space atau space minus 1 less or equal than x less or equal than 1 space atau space x greater or equal than 3 close curly brackets end cell end table 

Pembahasan

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar x squared minus 5 close vertical bar end cell greater or equal than 4 row cell x squared minus 5 end cell less or equal than cell negative 4 space atau space x squared minus 5 greater or equal than 4 end cell row cell x squared minus 5 plus 4 end cell less or equal than cell 0 space atau space x squared minus 5 minus 4 greater or equal than 0 end cell row cell x squared minus 1 end cell less or equal than cell 0 space atau space x squared minus 9 greater or equal than 0 end cell row cell left parenthesis x plus 1 right parenthesis left parenthesis x minus 1 right parenthesis end cell less or equal than cell 0 space atau space left parenthesis x plus 3 right parenthesis left parenthesis x minus 3 right parenthesis greater or equal than 0 end cell row cell negative 1 end cell less or equal than cell x less or equal than 1 space atau space x less or equal than negative 3 space atau space x greater or equal than 3 end cell row x less or equal than cell negative 3 space atau space minus 1 less or equal than x less or equal than 1 space atau space x greater or equal than 3 end cell end table 

Jadi, himpunan penyelesaian dari pertidaksamaan open vertical bar x squared minus 5 close vertical bar greater or equal than 4 adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open curly brackets right enclose x x less or equal than negative 3 space atau space minus 1 less or equal than x less or equal than 1 space atau space x greater or equal than 3 close curly brackets end cell end table 

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Tentukan himpunan penyelesaian dari setiap pertidaksamaan nilai mutlak di bawah ini. b. ∣∣​x2−x−1∣∣​​>​1​

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