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Tentukan bayangan titik  Oleh dilatasi: b.

Pertanyaan

Tentukan bayangan titik open parentheses 3 comma space minus 4 close parentheses Oleh dilatasi:

b. open square brackets open parentheses negative 1 comma space minus 1 close parentheses comma space 5 close square brackets

Pembahasan Soal:

Bayangan dilatasi terhadap titik pusat P open parentheses a comma space b close parentheses dengan faktor skala k adalah straight x apostrophe equals straight a plus straight k open parentheses straight x minus straight a close parentheses dan straight y apostrophe equals straight b plus straight k open parentheses straight y minus straight b close parentheses.

Sehingga diperoleh:

begin mathsize 12px style table attributes columnalign left center left end attributes row cell open parentheses straight x comma space straight y close parentheses end cell cell rightwards arrow with open square brackets open parentheses straight a comma space straight b close parentheses comma space straight k close square brackets on top end cell cell open parentheses straight a plus straight k open parentheses straight x minus straight a close parentheses comma space straight b plus straight k open parentheses straight y minus straight b close parentheses close parentheses end cell row cell open parentheses 3 comma space minus 4 close parentheses end cell cell rightwards arrow with open square brackets open parentheses negative 1 comma space minus 1 close parentheses comma space 5 close square brackets on top end cell cell open parentheses negative 1 plus 5 open parentheses 3 minus open parentheses negative 1 close parentheses close parentheses comma space minus 1 plus 5 open parentheses negative 4 minus open parentheses negative 1 close parentheses close parentheses close parentheses end cell row space space cell open parentheses negative 1 plus 5 open parentheses 3 plus 1 close parentheses comma space minus 1 plus 5 open parentheses negative 4 plus 1 close parentheses close parentheses end cell row space space cell open parentheses negative 1 plus 5 open parentheses 4 close parentheses comma space minus 1 plus 5 open parentheses negative 3 close parentheses close parentheses end cell row space space cell open parentheses negative 1 plus 20 comma space minus 1 plus open parentheses negative 15 close parentheses close parentheses end cell row space space cell open parentheses 19 comma space minus 1 minus 15 close parentheses end cell row space space cell open parentheses 19 comma space minus 16 close parentheses end cell end table end style

Maka, bayangan titik open parentheses 3 comma space minus 4 close parentheses dilatasi oleh open square brackets open parentheses negative 1 comma space minus 1 close parentheses comma space 5 close square brackets adalah open parentheses 19 comma space minus 16 close parentheses.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 18 Juli 2021

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