Roboguru
SD

T entukan nilai dari: b. n=1∑5​(log 2n−20)

Pertanyaan

T entukan nilai dari:

b. sum from n equals 1 to 5 of left parenthesis log space 2 to the power of n minus 20 right parenthesis 

H. Eka

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

nilai dari table attributes columnalign right center left columnspacing 0px end attributes row cell sum from n equals 1 to 5 of left parenthesis log space 2 to the power of n minus 20 right parenthesis end cell equals cell log space 2 to the power of 15 minus 100 end cell end table

Pembahasan

Jawaban yang benar untuk pertanyaan tersebut adalah table attributes columnalign right center left columnspacing 0px end attributes row cell sum from n equals 1 to 5 of left parenthesis log space 2 to the power of n minus 20 right parenthesis end cell equals cell log space 2 to the power of 15 minus 100 end cell end table

Jika suatu barisan dinyatakan dengan: U subscript 1 comma space U subscript 2 comma space U subscript 3 comma space horizontal ellipsis comma space U subscript n equals open curly brackets U subscript n close curly brackets, maka deret yang diperoleh dari barisan tersebut dapat dirumuskan sebagai berikut.

U subscript 1 plus U subscript 2 plus U subscript 3 plus... plus U subscript n equals sum from i equals 1 to n of U subscript i

Pada soal diketahui notasi sigma: sum from n equals 1 to 5 of left parenthesis log space 2 to the power of n minus 20 right parenthesis

Notasi sigma tersebut dapat dijabarkan menjadi bentuk penjumlahan sebagai berikut.

begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell sum from n equals 1 to 5 of left parenthesis log space 2 to the power of n minus 20 right parenthesis end cell equals cell open parentheses log space 2 minus 20 close parentheses plus open parentheses log space 2 squared minus 20 close parentheses plus open parentheses log space 2 cubed minus 20 close parentheses end cell row blank blank cell plus open parentheses log space 2 to the power of 4 minus 20 close parentheses plus open parentheses log space 2 to the power of 5 minus 20 close parentheses end cell row blank equals cell log space 2 times 2 squared times 2 cubed times 2 to the power of 4 times 2 to the power of 5 minus 100 end cell row blank equals cell log space 2 to the power of 15 minus 100 end cell end table end style

Dengan demikian, nilai dari table attributes columnalign right center left columnspacing 0px end attributes row cell sum from n equals 1 to 5 of left parenthesis log space 2 to the power of n minus 20 right parenthesis end cell equals cell log space 2 to the power of 15 minus 100 end cell end table

29

0.0 (0 rating)

Pertanyaan serupa

n=1∑5​(2n−1)=...

35

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia