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Pertanyaan

Supaya ∣ ∣ ​ 2 lo g ( 3 x − 1 ) ∣ ∣ ​ < 3 maka ...

Supaya  maka ...

  1. 1 third less than x less than 3 

  2. 0 less than x less than 3 over 8 

  3. 0 less than x less than 3 over 8 atau x greater than 3 

  4. 3 over 8 less than x less than 3 

  5. x less than 3 over 8 atau x greater than 3 

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D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah D.

jawaban yang benar adalah D.

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Pembahasan

Diketahui : Ingat kembali bahwa : Maka Syarat (i) Syarat (ii) Syarat (iii) Jadi, penyelesaiannya adalah irisian dari dengan dan yaitu Oleh karena itu, jawaban yang benar adalah D.

Diketahui : open vertical bar log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis close vertical bar less than 3

Ingat kembali bahwa :

bullet space open vertical bar f left parenthesis x right parenthesis close vertical bar less than a comma space a greater than 0 rightwards arrow space minus a less than f left parenthesis x right parenthesis less than a bullet space log presuperscript a space f left parenthesis x right parenthesis less than log presuperscript a space g left parenthesis x right parenthesis comma space a greater than 1 rightwards arrow 0 less than f left parenthesis x right parenthesis less than g left parenthesis x right parenthesis bullet space log presuperscript a space a to the power of m equals m     

Maka

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis close vertical bar end cell less than 3 row cell negative 3 end cell less than cell log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis less than 3 end cell end table   

Syarat (i)  3 x minus 1 greater than 0 

table attributes columnalign right center left columnspacing 0px end attributes row cell 3 x minus 1 end cell greater than 0 row cell 3 x end cell greater than 1 row x greater than cell 1 third end cell end table 

Syarat (ii) log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis greater than negative 3    

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis end cell greater than cell negative 3 end cell row cell log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis end cell greater than cell scriptbase log space 2 to the power of negative 3 end exponent end scriptbase presuperscript 2 end cell row cell log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis end cell greater than cell log presuperscript 2 space 1 over 8 end cell row cell 3 x minus 1 end cell greater than cell 1 over 8 end cell row cell 3 x end cell greater than cell 1 over 8 plus 1 end cell row cell 3 x end cell greater than cell 9 over 8 end cell row x greater than cell fraction numerator begin display style 9 over 8 end style over denominator 3 end fraction end cell row x greater than cell 3 over 8 end cell end table 

Syarat (iii) log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis less than 3

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis end cell less than 3 row cell log presuperscript 2 left parenthesis 3 x minus 1 right parenthesis end cell less than cell scriptbase log space 2 cubed end scriptbase presuperscript 2 end cell row cell 3 x minus 1 end cell less than cell 2 cubed end cell row cell 3 x end cell less than cell 8 plus 1 end cell row cell 3 x end cell less than 9 row x less than cell 9 over 3 end cell row x less than 3 end table  

Jadi, penyelesaiannya adalah irisian dari x greater than 1 thirddengan x greater than 3 over 8 dan x less than 3 yaitu 3 over 8 less than x less than 3 

Oleh karena itu, jawaban yang benar adalah D.

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