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Pertanyaan

Pertidaksamaan 3 lo g { 2 lo g ∣ ∣ ​ 2 lo g x ∣ ∣ ​ } < 0 dipenuhi untuk ...

Pertidaksamaan  dipenuhi untuk ...

  1. 0 less than x less than 4 

  2. 0 less than x less than 2 

  3. 1 fourth less than x less than 1 half atau 2 less than x less than 4 

  4. 1 half less than x less than 2 

  5. 1 fourth less than x less than 4 

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D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.

jawaban yang benar adalah C.

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Pembahasan

Diketahui : Ingat kembali : Sehingga Syarat untuk untuk maka penyelesaian dari adalah Jadi penyelesaiannya adalah irisan dari dengan yaitu atau . Oleh karena itu, jawaban yang benar adalah C.

Diketahui : log presuperscript 3 space open curly brackets log presuperscript 2 space open vertical bar log presuperscript 2 space x close vertical bar close curly brackets less than 0

Ingat kembali :

bullet space log presuperscript straight a space 1 equals 0 bullet space log presuperscript straight a space straight a equals 1 bullet space log presuperscript straight a space straight a to the power of straight m equals straight m bullet space straight a to the power of negative straight m end exponent equals 1 over straight a to the power of straight m bullet space open vertical bar straight x close vertical bar less than straight a comma space straight a greater than 0 rightwards arrow negative straight a less than straight x less than straight a bullet space open vertical bar straight x close vertical bar greater than straight a comma space straight a greater than 0 rightwards arrow straight x less than negative straight a space atau space straight x greater than straight a bullet space log presuperscript straight a space f left parenthesis x right parenthesis less than log presuperscript straight a space straight b comma space straight a greater than 1 rightwards arrow 0 less than f left parenthesis x right parenthesis less than straight b bullet space log presuperscript straight a space f left parenthesis x right parenthesis greater than log presuperscript straight a space straight b comma space straight a greater than 1 rightwards arrow f left parenthesis x right parenthesis greater than straight b greater than 0  

Sehingga 

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 3 space open curly brackets log presuperscript 2 space open vertical bar log presuperscript 2 space x close vertical bar close curly brackets end cell less than 0 row cell log presuperscript 3 space space open curly brackets log presuperscript 2 space open vertical bar log presuperscript 2 space x close vertical bar close curly brackets end cell less than cell log presuperscript 3 space 1 end cell row cell space log presuperscript 2 space open vertical bar log presuperscript 2 space x close vertical bar end cell less than 1 row cell space log presuperscript 2 space open vertical bar log presuperscript 2 space x close vertical bar end cell less than cell log presuperscript 2 space 2 end cell row cell open vertical bar log presuperscript 2 space x close vertical bar end cell less than 2 row cell negative 2 end cell less than cell log presuperscript 2 space x less than 2 end cell row cell log presuperscript 2 space 2 to the power of negative 2 end exponent end cell less than cell log presuperscript 2 space x less than log presuperscript 2 space 2 squared end cell row cell 2 to the power of negative 2 end exponent end cell less than cell x less than 2 squared end cell row cell 1 fourth end cell less than cell x less than 4 end cell end table 

Syarat log presuperscript 2 open vertical bar log presuperscript 2 space x close vertical bar greater than 0 

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 2 open vertical bar log presuperscript 2 space x close vertical bar end cell greater than 0 row cell log presuperscript 2 open vertical bar log presuperscript 2 space x close vertical bar end cell greater than cell log presuperscript 2 space 1 end cell row cell open vertical bar log presuperscript 2 space x close vertical bar end cell greater than 1 row cell log presuperscript 2 space x end cell less than cell negative 1 space atau space log presuperscript 2 space x greater than 1 end cell end table  

untuk log presuperscript 2 space x less than negative 1 

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 2 space x end cell less than cell negative 1 end cell row cell log presuperscript 2 space x end cell less than cell log presuperscript 2 space 2 to the power of negative 1 end exponent end cell row x less than cell 1 half end cell end table 

untuk log presuperscript 2 space x greater than 1 

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 2 space x end cell greater than 1 row cell log presuperscript 2 space x end cell greater than cell log presuperscript 2 space 2 end cell row x greater than 2 end table 

maka penyelesaian dari log presuperscript 2 open vertical bar log presuperscript 2 space x close vertical bar greater than 0 adalah x less than 1 half space atau space x greater than 2 

Jadi penyelesaiannya adalah irisan dari 1 fourth less than x less than 4 dengan x less than 1 half space atau space x greater than 2 yaitu 1 fourth less than x less than 1 half atau 2 less than x less than 4.

Oleh karena itu, jawaban yang benar adalah C.

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