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Pertanyaan

Jika 3 lo g ∣ x − 1 ∣ < 2 maka ...

Jika  maka ...

  1. negative 8 less than x less than 10 

  2. negative 8 less than x less than 1 

  3. 1 less than x less than 10 

  4. negative 8 less than x less than 1 atau 1 less than x less than 10 

  5. x greater than 10 

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D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah D.

jawaban yang benar adalah D.

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Pembahasan

Ingat kembali bahwa : Diketahui : Syarat (i) Syarat (ii) Syarat (iii) Jadi, penyelesaiannya adalah irisan dengan dan yaitu atau Oleh karena itu, jawaban yang benar adalah D.

Ingat kembali bahwa :

bullet space open vertical bar f left parenthesis x right parenthesis close vertical bar less than a comma space a greater than 0 rightwards arrow negative a less than f left parenthesis x right parenthesis less than a bullet space log presuperscript a space f left parenthesis x right parenthesis less than log presuperscript a space g left parenthesis x right parenthesis comma space a greater than 1 rightwards arrow 0 less than f left parenthesis x right parenthesis less than g left parenthesis x right parenthesis bullet space log presuperscript a space a to the power of m equals m   

 Diketahui : log presuperscript 3 open vertical bar x minus 1 close vertical bar less than 2

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 3 open vertical bar x minus 1 close vertical bar end cell less than 2 row cell log presuperscript 3 open vertical bar x minus 1 close vertical bar end cell less than cell scriptbase log space 3 squared end scriptbase presuperscript 3 end cell row cell open vertical bar x minus 1 close vertical bar end cell less than cell 3 squared end cell row cell open vertical bar x minus 1 close vertical bar end cell less than 9 row cell negative 9 end cell less than cell x minus 1 less than 9 end cell end table  

Syarat (i) open vertical bar x minus 1 close vertical bar greater than 0 

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar x minus 1 close vertical bar end cell greater than 0 row cell x minus 1 end cell greater than cell 0 space atau space x minus 1 less than 0 end cell row x greater than cell 1 space atau space x less than 1 end cell end table   

Syarat (ii) x minus 1 greater than negative 9 

table attributes columnalign right center left columnspacing 0px end attributes row cell x minus 1 end cell greater than cell negative 9 end cell row x greater than cell negative 9 plus 1 end cell row x greater than cell negative 8 end cell end table   

Syarat (iii) x minus 1 less than 9 

table attributes columnalign right center left columnspacing 0px end attributes row cell x minus 1 end cell less than 9 row x less than cell 9 plus 1 end cell row x less than 10 end table 

Jadi, penyelesaiannya adalah irisan x greater than 1 space atau space x less than 1 dengan x greater than negative 8 dan x less than 10 yaitu negative 8 less than x less than 1 atau 1 less than x less than 10 

Oleh karena itu, jawaban yang benar adalah D.

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