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Suku ke-lima dari penjabaran  adalah ....

Pertanyaan

Suku ke-lima dari penjabaran undefined adalah ....

  1. begin mathsize 14px style 12 x to the power of 5 y squared end style 

  2. begin mathsize 14px style 12 x to the power of 4 y cubed end style 

  3. begin mathsize 14px style 945 x cubed y to the power of 4 end style 

  4. begin mathsize 14px style 1.215 x squared y to the power of 5 end style 

  5. begin mathsize 14px style 955 x cubed y to the power of 4 end style 

Pembahasan Video:

Pembahasan Soal:

Dengan menggunakan rumus kombinasi

begin mathsize 14px style C subscript open parentheses n comma r close parentheses end subscript equals fraction numerator n factorial over denominator open parentheses n minus r close parentheses factorial times r factorial end fraction end style

dan rumus Binomial Newton

begin mathsize 14px style open parentheses a plus b close parentheses to the power of n equals sum from r equals 0 to n of C subscript left parenthesis n comma r right parenthesis end subscript times a to the power of n minus r end exponent times b to the power of r end style

akibatnya, suku ke-lima dari penjabaran begin mathsize 14px style left parenthesis 3 x plus y right parenthesis to the power of 7 end style dapat diselesaikan sebagai berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row a equals cell 3 x end cell row b equals y row n equals 7 row r equals cell 5 minus 1 equals 4 end cell end table end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell C subscript open parentheses n comma r close parentheses end subscript times a to the power of n minus r end exponent times b to the power of r end cell equals cell C subscript open parentheses 7 comma 4 close parentheses end subscript times open parentheses 3 x close parentheses to the power of 7 minus 4 end exponent times y to the power of 4 end cell row blank equals cell fraction numerator 7 factorial over denominator open parentheses 7 minus 4 close parentheses factorial times 4 factorial end fraction times open parentheses 3 x close parentheses cubed times y to the power of 4 end cell row blank equals cell fraction numerator 7 times 6 times 5 times 4 factorial over denominator 3 factorial times 4 factorial end fraction times 27 x cubed times y to the power of 4 end cell row blank equals cell fraction numerator 7 times 6 times 5 over denominator 3 times 2 times 1 end fraction times 27 x cubed y to the power of 4 end cell row blank equals cell fraction numerator 7 times 6 times 5 over denominator 6 end fraction times 27 x cubed y to the power of 4 end cell row blank equals cell 7 times 5 times 27 x cubed y to the power of 4 end cell row blank equals cell 945 x cubed y to the power of 4 end cell end table end style

Dengan demikian, suku ke-lima dari penjabaran undefined adalah begin mathsize 14px style 945 x cubed y to the power of 4 end style.

Jadi, jawaban yang tepat adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 05 Mei 2021

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