RoboguruRoboguru
SD

Suku banyak p(x) dibagi oleh (x2−1) sisanya (−x+4) dan jika dibagi oleh (x+3) sisanya 11. sisa pembagian suku banyak oleh (x2+2x−3) adalah ....

Pertanyaan

Suku banyak begin mathsize 14px style p open parentheses x close parentheses end style dibagi oleh begin mathsize 14px style open parentheses x squared minus 1 close parentheses end style sisanya begin mathsize 14px style open parentheses negative x plus 4 close parentheses end style dan jika dibagi oleh begin mathsize 14px style open parentheses x plus 3 close parentheses end style sisanya 11. sisa pembagian suku banyak oleh begin mathsize 14px style open parentheses x squared plus 2 x minus 3 close parentheses end style adalah ....

  1. begin mathsize 14px style negative 2 x plus 5 end style   

  2. begin mathsize 14px style 2 x plus 5 end style   

  3. begin mathsize 14px style negative 3 1 half x plus 6 1 half end style   

  4. begin mathsize 14px style negative 4 x plus 7 end style   

  5. begin mathsize 14px style 2 x plus 1 end style   

R. Novianto

Master Teacher

Mahasiswa/Alumni Universitas Tanjungpura Pontianak

Jawaban terverifikasi

Pembahasan

1. Suku banyak begin mathsize 14px style p open parentheses x close parentheses end style dibagi oleh begin mathsize 14px style open parentheses x squared minus 1 close parentheses end style sisanya begin mathsize 14px style open parentheses negative x plus 4 close parentheses end style , artinya :
 

begin mathsize 14px style straight p open parentheses straight x close parentheses colon open parentheses straight x squared minus 1 close parentheses space bersisa open parentheses negative straight x plus 4 close parentheses rightwards double arrow open parentheses straight x plus 1 close parentheses open parentheses straight x minus 1 close parentheses rightwards double arrow straight x equals negative 1 space atau space straight x equals 1 maka space semicolon table attributes columnalign right center left columnspacing 2px end attributes row cell straight p open parentheses negative 1 close parentheses end cell equals cell negative straight x plus 4 end cell row blank equals cell negative open parentheses negative 1 close parentheses plus 4 end cell row blank equals 5 row blank blank blank row cell straight p open parentheses 1 close parentheses end cell equals cell negative straight x plus 4 end cell row blank equals cell negative open parentheses 1 close parentheses plus 4 end cell row blank equals 3 end table end style 
 

2. Suku banyak begin mathsize 14px style p open parentheses x close parentheses end style dibagi oleh begin mathsize 14px style open parentheses x plus 3 close parentheses end style sisanya 11, artinya :
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell straight p open parentheses straight x close parentheses space colon space open parentheses straight x plus 3 close parentheses end cell rightwards arrow cell sisa space 11 end cell row blank rightwards double arrow cell straight x equals negative 3 end cell row cell straight p open parentheses negative 3 close parentheses end cell equals 11 end table end style 
 

3. Jika Suku banyak begin mathsize 14px style p open parentheses x close parentheses end style dibagi oleh begin mathsize 14px style open parentheses x squared plus 2 x minus 3 close parentheses end style anggap sisanya begin mathsize 14px style ax plus straight b end style 
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell straight P open parentheses straight x close parentheses space colon space open parentheses straight x squared plus 2 straight x minus 3 close parentheses end cell rightwards arrow cell sisa space ax plus straight b end cell row cell open parentheses straight x plus 3 close parentheses open parentheses straight x minus 1 close parentheses end cell equals 0 row cell straight x equals negative 3 end cell blank cell atau space straight x equals 1 end cell row artinya colon blank row cell straight p open parentheses negative 3 close parentheses end cell equals cell ax plus straight b rightwards arrow sisa space 11 end cell row 11 equals cell negative 3 straight a plus straight b... open parentheses pers.1 close parentheses end cell row blank blank blank row cell straight p open parentheses 1 close parentheses end cell equals cell ax plus straight b rightwards arrow sisa space 5 end cell row 5 equals cell straight a plus straight b... open parentheses pers. space 2 close parentheses end cell end table end style  
 

Kemudian pers. 1 dan pers. 2 dieliminasi untuk memperoleh nilai a 

Error converting from MathML to accessible text. 

Selanjutnya nilai b disubstitusikan ker pers. 2

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell straight a plus straight b end cell equals 5 row cell negative 3 over 2 plus straight b end cell equals 5 row straight b equals cell 5 times open parentheses negative 2 over 3 close parentheses end cell row straight b equals cell negative 10 over 3 end cell end table end style 
 

sisa pembagian suku banyak oleh begin mathsize 14px style open parentheses x squared plus 2 x minus 3 close parentheses end style adalahbegin mathsize 14px style equals negative 3 over 2 straight x minus 10 over 3 end style 

Jadi, tidak ada pilihan jawaban yang tepat

 

145

4.8 (7 rating)

Pertanyaan serupa

Hasil dan sisa pembagian f(x)=x4+2x3−2x2+x+8 oleh (x+2) berturut-turut ....

1rb+

4.7

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia