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Suatu campuran penyangga yang terbentuk dari 500 mL larutan HCOOH 1 M dan 500 mL larutan HCOONa 1 M, ditambah 100 mL larutan yang pH-nya 1. Hitunglah pH sebelum dan sesudah ditambah larutan tersebut. (K a HCOOH = 2 x 10 -4 ).

Suatu campuran penyangga yang terbentuk dari 500 mL larutan HCOOH 1 M dan 500 mL larutan HCOONa 1 M, ditambah 100 mL larutan yang pH-nya 1. Hitunglah pH sebelum dan sesudah ditambah larutan tersebut. (Ka HCOOH = 2 x 10-4).
 

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Jawaban

pH setelah penambahan asam adalah 4-log2,1, dan sebelumnya 4-log 2

pH setelah penambahan asam adalah 4-log2,1, dan sebelumnya 4-log 2

Pembahasan

Menggunakan konsep larutan penyangga asam, Hitung konsentrasi H + Setelah penambahan larutan pH 1 reaksi setelah penambahan larutan, Jadi pH setelah penambahan asam adalah 4-log2,1, dan sebelumnya 4-log 2

Menggunakan konsep larutan penyangga asam, 

Hitung konsentrasi H+

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript a middle dot fraction numerator mol space asam over denominator mol space basa space konjugasi end fraction end cell row blank equals cell 2 cross times 10 to the power of negative sign 4 end exponent middle dot fraction numerator 0 comma 5 space mol over denominator 0 comma 5 space mol end fraction end cell row blank equals cell 2 cross times 10 to the power of negative sign 4 end exponent end cell end table  

table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log open square brackets 2 cross times 10 to the power of negative sign 4 end exponent close square brackets end cell row blank equals cell 4 minus sign log space 2 end cell end table 

Setelah penambahan larutan pH 1

table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row 1 equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 1 end exponent end cell row blank equals cell 0 comma 1 space M end cell row blank blank blank row cell n space H to the power of plus sign end cell equals cell 0 comma 1 cross times 100 end cell row blank equals cell 10 mmol end cell end table  

reaksi setelah penambahan larutan,

space space space space space space space space bold space H C O O to the power of bold minus sign bold space bold space bold space bold plus bold space bold space bold space bold space bold space H to the power of bold plus bold space bold space bold space end exponent bold space bold space bold space bold space bold rightwards arrow bold space bold space bold space bold space H C O O H M space space space space space space 0 comma 5 space mol space space space space space space space space space 0 comma 01 space mol space space space space space space space space space space space 0 comma 5 space mol B space space space space space space 0 comma 01 space mol space space space space space space space space 0 comma 01 space mol space space space space space space space space space space 0 comma 01 space mol S space space space space space space 0 comma 49 space mol space space space space space space space space minus sign space space space space space space space space space space space space space space space space space space space space space 0 comma 51 space mol space space 

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript a middle dot fraction numerator n space H C O O H over denominator n space H C O O Na end fraction end cell row blank equals cell 2 cross times 10 to the power of negative sign 4 end exponent cross times fraction numerator 0 comma 51 over denominator 0 comma 49 end fraction end cell row blank equals cell 2 comma 1 cross times 10 to the power of negative sign 4 end exponent end cell row blank blank blank row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log open square brackets 2 comma 1 cross times 10 to the power of negative sign 4 end exponent close square brackets end cell row blank equals cell 4 minus sign log space 2 comma 1 end cell end table 

Jadi pH setelah penambahan asam adalah 4-log2,1, dan sebelumnya 4-log 2

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