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Setarakan reaksi redoks berikut.  (suasana basa)

Setarakan reaksi redoks berikut.


begin mathsize 14px style Cl subscript 2 open parentheses italic a italic q close parentheses plus I O subscript 3 to the power of minus sign open parentheses italic a italic q close parentheses yields Cl to the power of minus sign open parentheses italic a italic q close parentheses plus I O subscript 4 to the power of minus sign open parentheses italic a italic q close parentheses end style (suasana basa)

  1. ... space  

  2. ... undefined 

Jawaban:

Tentukan atom yang mengalami perubahan bilangan oksidasi dan setarakan jumlah atom yang berubah bilangan oksidasinya.undefined 

undefined 

Kalikan pengali dengan koefisien:undefined 

begin mathsize 14px style Cl subscript 2 left parenthesis italic a italic q right parenthesis plus I O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis yields 2 Cl to the power of minus sign left parenthesis italic a italic q right parenthesis plus I O subscript 4 to the power of minus sign left parenthesis italic a italic q right parenthesis end style 

Setarakan jumlah O dengan menambahkan undefined:undefined 

begin mathsize 14px style Cl subscript 2 left parenthesis italic a italic q right parenthesis plus I O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis plus H subscript bold 2 O bold open parentheses italic l bold close parentheses yields 2 Cl to the power of minus sign left parenthesis italic a italic q right parenthesis plus I O subscript 4 to the power of minus sign left parenthesis italic a italic q right parenthesis end style 

Setarakan jumlah H dengan menambahkan ion undefined:undefined 

begin mathsize 14px style Cl subscript 2 left parenthesis italic a italic q right parenthesis plus I O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis plus H subscript 2 O open parentheses italic l close parentheses yields 2 Cl to the power of minus sign left parenthesis italic a italic q right parenthesis plus I O subscript 4 to the power of minus sign left parenthesis italic a italic q right parenthesis plus bold 2 H to the power of bold plus sign bold left parenthesis italic a italic q bold right parenthesis end style 

Tambahkan ion undefined di kedua ruas sebanyak jumlah ion undefined:undefined 

begin mathsize 14px style Cl subscript 2 left parenthesis italic a italic q right parenthesis plus I O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis plus H subscript 2 O open parentheses italic l close parentheses and bold 2 O H to the power of bold minus sign bold left parenthesis italic a italic q bold right parenthesis yields 2 Cl to the power of minus sign left parenthesis italic a italic q right parenthesis plus I O subscript 4 to the power of minus sign left parenthesis italic a italic q right parenthesis plus 2 H to the power of plus sign left parenthesis italic a italic q right parenthesis plus bold 2 O H to the power of bold minus sign bold left parenthesis italic a italic q bold right parenthesis end style 

Ion undefined dan undefined akan membentuk undefined. Eliminasi undefined pada kedua ruas sehingga diperoleh reaksi setara:

begin mathsize 14px style Cl subscript 2 left parenthesis italic a italic q right parenthesis plus I O subscript 3 to the power of minus sign left parenthesis italic a italic q italic right parenthesis plus 2 O H to the power of minus sign left parenthesis italic a italic q right parenthesis yields 2 Cl to the power of minus sign left parenthesis italic a italic q right parenthesis plus I O subscript 4 to the power of minus sign left parenthesis italic a italic q right parenthesis plus H subscript 2 O open parentheses italic l close parentheses end style 

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