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Setarakan reaksi redoks berikut. (suasana asam)

Setarakan reaksi redoks berikut.


begin mathsize 14px style Cr subscript 2 O subscript 7 to the power of 2 minus sign open parentheses italic a italic q close parentheses plus C subscript 2 O subscript 4 to the power of 2 minus sign open parentheses italic a italic q close parentheses yields Cr to the power of 3 plus sign open parentheses italic a italic q close parentheses plus C O subscript 2 open parentheses italic a italic q close parentheses end style (suasana asam)

  1. ... space  

  2. ... undefined 

Jawaban:

Tentukan atom yang mengalami perubahan bilangan oksidasi dan setarakan jumlah atom yang berubah bilangan oksidasinya.

undefined 

Kalikan pengali dengan koefisien:undefined 

begin mathsize 14px style Cr subscript 2 O subscript 7 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis plus bold 3 C subscript 2 O subscript 4 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis yields bold 2 Cr to the power of 3 plus sign left parenthesis italic a italic q right parenthesis plus bold 6 C O subscript 2 open parentheses italic g close parentheses end style 

Setarakan jumlah O dengan menambahkan undefined:

begin mathsize 14px style Cr subscript 2 O subscript 7 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis plus 3 C subscript 2 O subscript 4 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis yields 2 Cr to the power of 3 plus sign left parenthesis italic a italic q right parenthesis plus 6 C O subscript 2 open parentheses italic g close parentheses and bold 7 H subscript bold 2 O bold open parentheses italic l bold close parentheses end style 

Setarakan jumlah H dengan menambahkan ion undefined:

begin mathsize 14px style Cr subscript 2 O subscript 7 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis plus 3 C subscript 2 O subscript 4 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis plus bold 14 H to the power of bold plus sign bold left parenthesis italic a italic q bold right parenthesis yields 2 Cr to the power of 3 plus sign left parenthesis italic a italic q right parenthesis plus 6 C O subscript 2 open parentheses italic g close parentheses and 7 H subscript 2 O open parentheses italic l close parentheses end style 

Jumlah atom dan muatan pada kedua ruas sudah setara.undefined 


Jadi, reaksi setara:

begin mathsize 14px style Cr subscript 2 O subscript 7 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis plus 3 C subscript 2 O subscript 4 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis plus 14 H to the power of plus sign left parenthesis italic a italic q right parenthesis yields 2 Cr to the power of 3 plus sign left parenthesis italic a italic q right parenthesis plus 6 C O subscript 2 open parentheses italic g close parentheses and 7 H subscript 2 O open parentheses italic l close parentheses end style 

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