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setarakan reaksi redoks berikut.  (suasana asam)

setarakan reaksi redoks berikut.


begin mathsize 14px style Zn open parentheses italic s close parentheses and N O subscript 3 to the power of minus sign open parentheses italic a italic q close parentheses yields Zn to the power of 2 plus sign open parentheses italic a italic q close parentheses plus N H subscript 4 to the power of plus sign open parentheses italic a italic q close parentheses end style (suasana asam)

  1. ... space  

  2. ... undefined 

Jawaban:

Tentukan atom yang mengalami perubahan bilangan oksidasi dan setarakan jumlah atom yang berubah bilangan oksidasinya:undefined 

undefinedundefined 

Setarakan jumlah O dengan menambahkan begin mathsize 14px style H subscript 2 O end style:undefined 

begin mathsize 14px style 4 Zn open parentheses italic s close parentheses plus N O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis yields 4 Zn to the power of 2 plus sign plus N H subscript 4 to the power of plus left parenthesis italic a italic q right parenthesis plus bold 3 H subscript bold 2 O bold open parentheses italic l bold close parentheses end style 

Setarakan jumlah H dengan menambahkan ion begin mathsize 14px style H to the power of plus sign end style:undefined 

begin mathsize 14px style 4 Zn open parentheses italic s close parentheses plus N O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis plus bold 10 H to the power of bold plus sign bold left parenthesis italic a italic q bold right parenthesis yields 4 Zn to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus N H subscript 4 to the power of plus left parenthesis italic a italic q right parenthesis plus 3 H subscript 2 O open parentheses italic l close parentheses end style  

Jumlah atom dan muatan pada kedua ruas sudah setara.undefined


Jadi, reaksi setara:undefined 

begin mathsize 14px style 4 Zn open parentheses italic s close parentheses plus N O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis plus 10 H to the power of plus sign left parenthesis italic a italic q right parenthesis yields 4 Zn to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus N H subscript 4 to the power of plus left parenthesis italic a italic q right parenthesis plus 3 H subscript 2 O open parentheses italic l close parentheses end style 

 

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