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Setarakan persamaan reaksi redoks berikut: 

begin mathsize 14px style N O subscript 3 to the power of minus sign and S to the power of 2 minus sign yields N O and S space open parentheses asam close parentheses end style 

G. Suprobo

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

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persamaan reaksi  redoks dalam suasana asam pada begin mathsize 14px style N O subscript 3 to the power of minus sign and S to the power of 2 minus sign yields N O and S end style adalah begin mathsize 14px style 2 N O subscript 3 to the power of minus sign and 3 S to the power of 2 minus sign and 8 H to the power of plus sign yields 2 N O and 3 S and 4 H subscript 2 O end style .

Pembahasan

Penyetaraan reaksi redoks dalam suasana asam dengan cara bilangan oksidasi :begin mathsize 14px style N O subscript 3 to the power of minus sign and S to the power of 2 minus sign yields N O and S space open parentheses asam close parentheses end style

1. Menentukan biloks masing- masing unsur

biloks N pada begin mathsize 14px style N O subscript 3 to the power of minus sign end style adalah +5.

  • begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell biloks space N plus left parenthesis 3 x left parenthesis minus sign 2 right parenthesis right parenthesis end cell equals cell negative sign 1 end cell row cell biloks space N minus sign 6 end cell equals cell negative sign 1 end cell row cell biloks space N end cell equals cell plus 5 end cell end table end style 

biloks N pada NO adalah +2.

  • begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell biloks space N minus sign 2 end cell equals 0 row cell biloks space N end cell equals cell plus 2 end cell end table end style 

biloks begin mathsize 14px style S to the power of 2 minus sign end style adalah -2

biloks S adalah 0

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell N O subscript 3 to the power of minus sign and S to the power of 2 minus sign end cell rightwards arrow cell N O and S end cell row blank blank cell plus 5 space space minus sign 2 space space space space space space plus 2 space space space space space space space 0 end cell end table end style  

2. Setarakan atom atom yang berubah bilangan oksidasinya.

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3. Tentukan jumlah kenaikan dan penurunan bilangan oksidasi dengan mengalikannya dengan indeks.

begin mathsize 14px style N O subscript 3 to the power of minus sign and S to the power of 2 minus sign yields N O and S space space space space space space space space space minus sign 2 space space space space space space space space space space space space space space 0 space space space end style  Terjadi peningkatan biloks S dari -2 menjadi 0.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell N O subscript 3 to the power of minus sign and S to the power of 2 minus sign end cell rightwards arrow cell N O and S end cell row blank blank cell plus 5 space space space space space space space space space space space space space plus 2 space space space space space space space end cell end table end style  Terjadi penurunan biloks N dari +5 menjadi +2.

4. Setarakan Jumlah kenaikan dan jumlah penurunan.

begin mathsize 14px style 2 N O subscript 3 to the power of minus sign and 3 S to the power of 2 minus sign yields 2 N O and 3 S end style   

5. Setarakan jumlah O dengan cara menambahkan H₂O di ruas kekurangan O sebanyak kekurangannya.

begin mathsize 14px style 2 N O subscript 3 to the power of minus sign and 3 S to the power of 2 minus sign yields 2 N O and 3 S and 4 H subscript 2 O end style 

6. Setarakan Jumlah H dengan menambahkan H⁺ diruas kekurangan H sebanyak kekurangannya.

begin mathsize 14px style 2 N O subscript 3 to the power of minus sign and 3 S to the power of 2 minus sign and 8 H to the power of plus sign yields 2 N O and 3 S and 4 H subscript 2 O end style  

Jadi, persamaan reaksi  redoks dalam suasana asam pada begin mathsize 14px style N O subscript 3 to the power of minus sign and S to the power of 2 minus sign yields N O and S end style adalah begin mathsize 14px style 2 N O subscript 3 to the power of minus sign and 3 S to the power of 2 minus sign and 8 H to the power of plus sign yields 2 N O and 3 S and 4 H subscript 2 O end style .

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