Roboguru
SD
SMP
SMA
UTBK/SNBT

Iklan

Iklan

Pertanyaan

Selesaikan setiap pertidaksamaan berikut. a. 1 ​ < ​ ∣ 2 x − 1 ∣ < 3 ​

Selesaikan setiap pertidaksamaan berikut.

a.  

Ke roboguru plus

Iklan

I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Jawaban

penyelesaian pertidaksamaan adalah

penyelesaian pertidaksamaan table attributes columnalign right center left columnspacing 0px end attributes row 1 less than cell open vertical bar 2 x minus 1 close vertical bar less than 3 end cell end table adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 1 end table table attributes columnalign right center left columnspacing 0px end attributes row blank less than blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank x end table table attributes columnalign right center left columnspacing 0px end attributes row blank less than blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 0 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank atau end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 1 end table table attributes columnalign right center left columnspacing 0px end attributes row blank less than blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank x end table table attributes columnalign right center left columnspacing 0px end attributes row blank less than blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table 

Iklan

Pembahasan

Jadi, penyelesaian pertidaksamaan adalah

table attributes columnalign right center left columnspacing 0px end attributes row 1 less than cell open vertical bar 2 x minus 1 close vertical bar less than 3 end cell row 1 less than cell open vertical bar 2 x minus 1 close vertical bar space dan space open vertical bar 2 x minus 1 close vertical bar less than 3 end cell row cell open vertical bar 2 x minus 1 close vertical bar end cell greater than cell 1 space dan space open vertical bar 2 x minus 1 close vertical bar less than 3 end cell row blank blank cell open parentheses 2 x minus 1 less than negative 1 space atau space 2 x minus 1 greater than 1 close parentheses space dan space open parentheses negative 3 less than 2 x minus 1 less than 3 close parentheses end cell row blank blank cell open parentheses 2 x less than negative 1 plus 1 space atau space 2 x greater than 1 plus 1 close parentheses space dan space open parentheses negative 3 plus 1 less than 2 x minus 1 plus 1 less than 3 plus 1 close parentheses end cell row blank blank cell open parentheses 2 x less than 0 space atau space 2 x greater than 2 close parentheses space dan space open parentheses negative 2 less than 2 x less than 4 close parentheses end cell row blank blank cell open parentheses x less than 0 space atau space x greater than 1 close parentheses space dan space open parentheses negative 1 less than x less than 2 close parentheses end cell row cell negative 1 end cell less than cell x less than 0 space atau space 1 less than x less than 2 end cell end table

Jadi, penyelesaian pertidaksamaan table attributes columnalign right center left columnspacing 0px end attributes row 1 less than cell open vertical bar 2 x minus 1 close vertical bar less than 3 end cell end table adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 1 end table table attributes columnalign right center left columnspacing 0px end attributes row blank less than blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank x end table table attributes columnalign right center left columnspacing 0px end attributes row blank less than blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 0 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank atau end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 1 end table table attributes columnalign right center left columnspacing 0px end attributes row blank less than blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank x end table table attributes columnalign right center left columnspacing 0px end attributes row blank less than blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Iklan

Gold Icon

Klaim Gold gratis sekarang!

Dengan Gold kamu bisa tanya soal ke Forum sepuasnya, lho.

Pertanyaan serupa

Semua nilai x yang memenuhi pertidaksamaan 0 < ∣ x − 3 ∣ ≤ 3 adalah ...

5

5.0

Jawaban terverifikasi

Nilai x yang memenuhi pertidaksamaan 0 < ∣ x − 1 ∣ < 5 adalah ...

5

5.0

Jawaban terverifikasi

Iklan

Iklan

Tentukan penyelesaian dari pertidaksamaan 2 ≤ ∣ 2 x − 6 ∣ ≤ 4 !

2

0.0

Jawaban terverifikasi

Carilah batasan nilai x yang memenuhi PtNM berikut. a. ∣ x + 3 ∣ < ∣ 3 x − 1 ∣ < 4

46

5.0

Jawaban terverifikasi

Himpunan penyelesaian pertidaksamaan ∣ 3 x − 7 ∣ ≤ 8 adalah ...

8

1.0

Jawaban terverifikasi
Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Download di Google Play

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Bantuan & Panduan

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia