Iklan

Pertanyaan

Segitiga ABC siku-siku di C. apabila sin A = 0.5 , tentukan: b . sec A dan cot A

Segitiga ABC siku-siku di C. apabila , tentukan:

  

  1. begin mathsize 14px style... end style 

  2. begin mathsize 14px style... end style  

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

04

:

21

:

54

Klaim

Iklan

D. Enty

Master Teacher

Jawaban terverifikasi

Jawaban

.

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank sec end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight A end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 2 over 3 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 3 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank dan end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cot end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight A end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 3 end cell end table end style.

Pembahasan

Pembahasan
lock

Berdasarkan jawaban a. maka: Jadi, .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell sin space straight A end cell equals cell 0 comma 5 end cell row straight A equals cell 30 degree end cell end table end style 

Berdasarkan jawaban a. maka:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell cos space straight A end cell equals cell cos space 30 degree end cell row blank equals cell fraction numerator square root of 3 over denominator 2 end fraction end cell row cell sec space straight A end cell equals cell fraction numerator 1 over denominator cos space 30 degree end fraction end cell row blank equals cell fraction numerator 2 over denominator square root of 3 end fraction times fraction numerator square root of 3 over denominator square root of 3 end fraction end cell row blank equals cell 2 over 3 square root of 3 end cell row cell tan space straight A end cell equals cell tan space 30 degree end cell row blank equals cell fraction numerator square root of 3 over denominator 3 end fraction end cell row cell cot space straight A end cell equals cell fraction numerator 1 over denominator tan space straight A end fraction end cell row blank equals cell fraction numerator 3 over denominator square root of 3 end fraction times fraction numerator square root of 3 over denominator square root of 3 end fraction end cell row blank equals cell square root of 3 end cell end table end style  

Jadi, begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank sec end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight A end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 2 over 3 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 3 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank dan end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cot end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight A end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 3 end cell end table end style.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Yuwono Yuwono

Makasih ❤️

Annisa sadiah

Makasih ❤️

Iklan

Pertanyaan serupa

Tentukan perbandingan trigonometri sin β , cos β , tan β , cosec β , secan β dan cotan β pada segitiga berikut.

4

4.5

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia