Iklan

Pertanyaan

SBMPTN'15 TKPA 646/46 Diketahui a , b , x dan y adalah bilangan real positif. Jika a 3 ab ​ ​ 3 a 2 ​ ab ​ ​ = a x b y , maka x − y adalah ....

SBMPTN'15 TKPA 646/46 
Diketahui adalah bilangan real positif. Jika , maka adalah ....

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

01

:

16

:

03

:

16

Klaim

Iklan

E. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

Pembahasan

Ingat kembali aturan perpangkatan berikut! ( ab ) m ( a m ) n a m ⋅ b n b n a m ​ ​ = = = = ​ a m b n a mn a m + n a m − n ​ Dengan aturan di atas, didapat perhitungan sebagai berikut. Dengan demikian, nilai dari x − y adalah 6 1 ​ . Oleh karena itu, jawaban yang tepat adalah E.

Ingat kembali aturan perpangkatan berikut!

Dengan aturan di atas, didapat perhitungan sebagai berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator cube root of a squared end root square root of a b end root over denominator square root of a cube root of a b end root end root end fraction end cell equals cell a to the power of x b to the power of y end cell row cell fraction numerator a to the power of begin display style 2 over 3 end style end exponent open parentheses a b close parentheses to the power of begin display style 1 half end style end exponent over denominator open parentheses a open parentheses a b close parentheses to the power of begin display style 1 third end style end exponent close parentheses to the power of begin display style 1 half end style end exponent end fraction end cell equals cell a to the power of x b to the power of y end cell row cell fraction numerator a to the power of begin display style 2 over 3 end style end exponent a to the power of begin display style 1 half end style end exponent b to the power of begin display style 1 half end style end exponent over denominator a to the power of begin display style 1 half end style end exponent a to the power of begin display style 1 over 6 end style end exponent b to the power of begin display style 1 over 6 end style end exponent end fraction end cell equals cell a to the power of x b to the power of y end cell row cell fraction numerator a to the power of begin display style 2 over 3 plus end style end exponent to the power of begin display style 1 half end style end exponent b to the power of begin display style 1 half end style end exponent over denominator a to the power of begin display style 1 half end style end exponent to the power of begin display style plus 1 over 6 end style end exponent b to the power of 1 over 6 end exponent end fraction end cell equals cell a to the power of x b to the power of y end cell row cell fraction numerator a to the power of begin display style 7 over 6 end style end exponent b to the power of begin display style 1 half end style end exponent over denominator a to the power of begin display style 2 over 3 end style end exponent b to the power of begin display style 1 over 6 end style end exponent end fraction end cell equals cell a to the power of x b to the power of y end cell row cell a to the power of 7 over 6 minus 2 over 3 end exponent times b to the power of 1 half minus 1 over 6 end exponent end cell equals cell a to the power of x b to the power of y end cell row cell a to the power of 1 half end exponent b to the power of 1 third end exponent end cell equals cell a to the power of x b to the power of y end cell row blank blank blank row x equals cell 1 half end cell row y equals cell 1 third end cell row blank blank blank row cell x minus y end cell equals cell 1 half minus 1 third end cell row blank equals cell fraction numerator 3 minus 2 over denominator 6 end fraction end cell row blank equals cell 1 over 6 end cell end table

Dengan demikian, nilai dari  adalah .

Oleh karena itu, jawaban yang tepat adalah E.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

Iklan

Pertanyaan serupa

Nilai x yang memenuhi persamaan 1 6 2 x = ( 2 8 2 ​ ) ⋅ 2 x adalah...

1

3.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia