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Persamaan lingkaran dengan pusat (-1, 1) dan menyinggung garis 3 x − 4 y + 12 = 0 adalah ....

Persamaan lingkaran dengan pusat (-1, 1) dan menyinggung garis  adalah ....

  1. x squared plus y squared plus 2 x minus 2 y plus 1 equals 0

  2. x squared plus y squared plus 2 x minus 2 y minus 7 equals 0

  3. 4 x squared plus 4 y squared plus 8 x minus 8 y minus 17 equals 0

  4. x squared plus y squared plus 2 x minus 2 y minus 2 equals 0

  5. 4 x squared plus 4 y squared plus 8 x minus 8 y minus 1 equals 0

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begin mathsize 12px style A equals 3 comma space B equals negative 4 comma space C equals 12 comma space x equals negative 1 comma space y equals 1 J a r a k space t i t i k space left parenthesis negative 1 comma space 1 right parenthesis space k e space g a r i s space 3 x minus 4 y plus 12 equals 0 space a d a l a h r equals open vertical bar fraction numerator A x subscript 1 plus B y subscript 1 plus C over denominator square root of A squared plus B squared end root end fraction close vertical bar space space equals open vertical bar fraction numerator open parentheses 3 close parentheses open parentheses negative 1 close parentheses plus open parentheses negative 4 close parentheses open parentheses 1 close parentheses plus 12 over denominator square root of 3 squared plus open parentheses negative 4 close parentheses squared end root end fraction close vertical bar space space equals open vertical bar fraction numerator negative 3 minus 4 plus 12 over denominator 5 end fraction close vertical bar space space equals 1  M a k a space p e r s a m a a n space l i n g k a r a n space d e n g a n space p u s a t space P space left parenthesis negative 1 comma space 1 right parenthesis d a n space j a r i minus j a r i space 1 space a d a l a h open parentheses x minus a close parentheses squared plus open parentheses y minus b close parentheses squared equals r squared open parentheses x plus 1 close parentheses squared plus open parentheses y minus 1 close parentheses squared equals 1 squared x squared plus 2 x plus 1 plus y squared minus 2 y plus 1 equals 1 x squared plus y squared plus 2 x minus 2 y plus 1 equals 0 end style

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Posisi garis 2 x − y + 1 = 0 terhadap lingkaran x 2 + y 2 − 4 x − 2 y + 2 = 0 adalah ...

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