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Persamaan garis singgung hiperbola  di titik  adal...

Persamaan garis singgung hiperbola 4 x squared minus y squared minus 40 x minus 4 y plus 48 equals 0 di titik open parentheses 9 comma 2 close parentheses adalah ....

Jawaban:

Pertama, kita cek kedudukan titik open parentheses 9 comma 2 close parentheses terhadap hiperbola 4 x squared minus y squared minus 40 x minus 4 y plus 48 equals 0.


space space space space space space space space space space 4 x squared minus y squared minus 40 x minus 4 y plus 48...0 4 open parentheses 9 close parentheses squared minus open parentheses 2 close parentheses squared minus 40 open parentheses 9 close parentheses minus 4 open parentheses 2 close parentheses plus 48...0 space space space space space space space space space space space space space 324 minus 4 minus 360 minus 8 plus 48...0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 equals 0


Hal ini berarti titik open parentheses 9 comma 2 close parentheses berada di hiperbola 4 x squared minus y squared minus 40 x minus 4 y plus 48 equals 0.

Persamaan garis singgung hiperbola straight A x squared plus straight B y squared plus straight C x plus straight D y plus straight E equals 0 di titik open parentheses straight x subscript 1 comma straight y subscript 1 close parentheses adalah


table attributes columnalign right center left columnspacing 0px end attributes row cell straight A times straight x subscript 1 times x plus straight B times straight y subscript 1 times straight y plus 1 half straight C open parentheses x plus straight x subscript 1 close parentheses plus 1 half straight D open parentheses y plus straight y subscript 1 close parentheses plus straight E end cell equals 0 row cell 4 times 9 x minus 2 times y minus 1 half times 40 open parentheses x plus 9 close parentheses minus 1 half times 4 open parentheses y plus 2 close parentheses plus 48 end cell equals 0 row cell 36 x minus 2 y minus 20 open parentheses x plus 9 close parentheses minus 2 open parentheses y plus 2 close parentheses plus 48 end cell equals 0 row cell 36 x minus 2 y minus 20 x minus 180 minus 2 y minus 4 plus 48 end cell equals 0 row cell 16 x minus 4 y minus 136 end cell equals 0 row cell 4 x minus y minus 34 end cell equals 0 end table


Jadi persamaan garis singgungnya adalah 4 x minus y minus 34 equals 0.

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