Roboguru

Perhatikan gambar rangkaian kapasitor berikut! Besarnya energi listrik pada kapasitor gabungan adalah ....

Perhatikan gambar rangkaian kapasitor berikut!

Besarnya energi listrik pada kapasitor gabungan adalah .... left parenthesis 1 space mu F space equals space 10 to the power of negative 6 end exponent space F right parenthesis

  1. 0 comma 6 cross times 10 to the power of negative 3 end exponent space J

  2. 1 comma 2 cross times 10 to the power of negative 3 end exponent space J

  3. 1 comma 8 cross times 10 to the power of negative 3 end exponent space J

  4. 2 comma 4 cross times 10 to the power of negative 3 end exponent space J

  5. 3 comma 6 cross times 10 to the power of negative 3 end exponent space J

Jawaban:

Ada dua kapasitas kapasitor yang dirangkai secara paralel.

C subscript P 1 end subscript equals 2 plus 2 equals 4 space mu F

Ada dua kapasitas kapasitor yang dirangkai secara paralel.

C subscript P 2 end subscript equals 2 plus 2 equals 4 space mu F

Lalu rangkai kembali secara seri. Maka :

1 over C subscript t o t a l end subscript space equals 1 over C subscript P 1 end subscript plus 1 over C subscript P 2 end subscript plus 1 over C subscript s  fraction numerator begin display style 1 end style over denominator begin display style C subscript t o t a l end subscript end style end fraction space equals space 1 fourth plus 1 fourth plus 1 half  fraction numerator begin display style 1 end style over denominator begin display style C subscript t o t a l end subscript end style end fraction space equals fraction numerator begin display style 1 end style over denominator begin display style 4 end style end fraction plus fraction numerator begin display style 1 end style over denominator begin display style 4 end style end fraction plus fraction numerator begin display style 2 end style over denominator begin display style 4 end style end fraction  C subscript t o t a l end subscript space equals space 4 over 4 space equals space 1 space mu F

Besar energi pada kapasitor gabungan adalah :

W space equals space 1 half C V squared  W subscript t o t a l space end subscript equals space 1 half C subscript t o t a l end subscript V squared subscript t o t a l end subscript  W subscript t o t a l space end subscript equals space 1 half left parenthesis 1 cross times 10 to the power of negative 6 end exponent right parenthesis left parenthesis 60 right parenthesis squared  W subscript t o t a l space end subscript equals 1 comma 8 cross times 10 to the power of negative 3 end exponent space J

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved