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Penyelesaian pertidaksamaan 2 lo g x . x + 1 lo g 4 < 2 − x + 1 lo g 4 adalah ....

Penyelesaian pertidaksamaan  adalah ....

  1. x > begin mathsize 14px style 1 third end style

  2. x > 1

  3. 0 < x < 1

  4. 0 < x < begin mathsize 14px style 1 third end style

  5. begin mathsize 14px style 1 third end style < x < 1

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F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

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Pembahasan

begin mathsize 14px style log presuperscript 2 invisible function application space straight x straight space. straight space log presuperscript straight x plus 1 end presuperscript space invisible function application 4 less than 2 minus log presuperscript straight x plus 1 end presuperscript space invisible function application 4  log presuperscript straight x plus 1 end presuperscript space invisible function application 2 squared straight space. straight space log presuperscript 2 space invisible function application straight x less than 2 straight space. straight space log presuperscript straight x plus 1 end presuperscript space invisible function application left parenthesis straight x plus 1 right parenthesis minus log presuperscript straight x plus 1 end presuperscript invisible function application space 4  2 straight space. straight space log presuperscript straight x plus 1 end presuperscript invisible function application space 2 space. space log presuperscript 2 invisible function application space straight x less than log presuperscript straight x plus 1 end presuperscript invisible function application space open parentheses straight x plus 1 close parentheses squared minus log presuperscript straight x plus 1 end presuperscript invisible function application space 4  2 straight space. straight space log presuperscript straight x plus 1 end presuperscript invisible function application space straight x less than log presuperscript straight x plus 1 end presuperscript invisible function application space open parentheses straight x plus 1 close parentheses squared over 4 straight space  log presuperscript straight x plus 1 end presuperscript invisible function application space straight x squared less than log presuperscript straight x plus 1 end presuperscript invisible function application space open parentheses straight x plus 1 close parentheses squared over 4 straight space  Syarat space numerus space logaritma colon space straight x greater than 0 horizontal ellipsis horizontal ellipsis horizontal ellipsis left parenthesis 1 right parenthesis  Maka space didapat space juga space basis space straight x plus 1 greater than 1 space dan space straight x plus 1 greater than 0 space left parenthesis memenuhi space syarat space basis right parenthesis comma  sehingga  straight x squared less than open parentheses straight x plus 1 close parentheses squared over 4  4 straight x squared less than straight x squared plus 2 straight x plus 1  4 straight x squared minus straight x squared minus 2 straight x minus 1 less than 0  3 straight x squared minus 2 straight x minus 1 less than 0  open parentheses 3 straight x plus 1 close parentheses open parentheses straight x minus 1 close parentheses less than 0 end style

begin mathsize 14px style negative 1 third less than straight x less than 1 horizontal ellipsis horizontal ellipsis horizontal ellipsis open parentheses 2 close parentheses    Irisan space dari space left parenthesis 1 right parenthesis space dan space left parenthesis 2 right parenthesis space yaitu space 0 less than straight x less than 1. end style

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