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Pertanyaan

Pada elektrolisis larutan begin mathsize 14px style Cu S O subscript 4 end style dihasilkan 25,4 gram endapan Cu pada katode. Hitung volume gas begin mathsize 14px style H subscript 2 end style begin mathsize 14px style left parenthesis 0 space degree C comma space 1 space atm right parenthesis end style yang dibebaskan pada elektrolisis larutan begin mathsize 14px style H subscript 2 S O subscript 4 end style encer dengan jumlah arus listrik yang sama. (Ar Cu = 63,5 dan O = 16) 

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

dapat disimpulkan volume begin mathsize 14px style H subscript 2 end style yang terbentuk sebanyak 8,96 L.

Pembahasan

Hukum Faraday II menyatakan "bahwa massa yang dihasilkan pada elektrode berbanding lurus dengan massa ekivalen zat".

  • Reaksi elektrolisis kedua larutan (reaksi pada katoda (K))

table attributes columnalign right center left columnspacing 0px end attributes row cell Cu S O subscript 4 end cell rightwards arrow cell Cu to the power of 2 plus sign space plus space S O subscript 4 to the power of 2 minus sign end exponent end cell row cell K space colon space Cu to the power of 2 plus space end exponent plus space 2 e space end cell rightwards arrow cell space Cu end cell row blank blank blank row cell H subscript 2 S O 4 space end cell rightwards arrow cell space 2 H to the power of plus sign space plus space S O subscript 4 to the power of 2 minus sign end exponent end cell row cell K space colon space 2 H subscript 2 O space plus space 2 e space end cell rightwards arrow cell space 2 O H to the power of minus sign space plus space H subscript 2 end cell end table

  • Menentukan W H subscript 2

table attributes columnalign right center left columnspacing 0px end attributes row cell W subscript Cu over W subscript H subscript 2 end subscript space end cell equals cell space ME subscript Cu over ME subscript H subscript 2 end subscript end cell row cell fraction numerator 25 comma 4 over denominator W subscript H subscript 2 end subscript end fraction end cell equals cell fraction numerator open parentheses fraction numerator 63 comma 5 over denominator 2 end fraction close parentheses over denominator open parentheses 1 over 1 close parentheses end fraction end cell row cell fraction numerator 25 comma 4 over denominator W subscript H subscript 2 end subscript end fraction space end cell equals cell space fraction numerator 31 comma 75 over denominator 1 end fraction end cell row cell W subscript H subscript 2 end subscript space end cell equals cell space fraction numerator 25 comma 4 space cross times space 1 space over denominator 31 comma 75 end fraction end cell row blank equals cell space 0 comma 8 space g end cell end table

  • H subscript 2

table attributes columnalign right center left columnspacing 0px end attributes row cell n space end cell equals cell space m over Mr end cell row blank equals cell space fraction numerator 0 comma 8 over denominator 2 end fraction end cell row blank equals cell space 0 comma 4 space mol end cell end table

  • Volume H subscript 2​​​​​​​ STP

table attributes columnalign right center left columnspacing 0px end attributes row cell V space H subscript 2 space end subscript open parentheses STP close parentheses space end cell equals cell space n space cross times space 22 comma 4 end cell row blank equals cell space 0 comma 4 space cross times 22 comma 4 end cell row blank equals cell space 8 comma 96 space L end cell end table

Jadi, dapat disimpulkan volume begin mathsize 14px style H subscript 2 end style yang terbentuk sebanyak 8,96 L.

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