Nilai x→4π​lim​(sin x − cos xcos 2x​)=....

Pertanyaan

Nilai limit as straight x rightwards arrow straight pi over 4 of open parentheses fraction numerator cos space 2 straight x over denominator sin space straight x space minus space cos space straight x end fraction close parentheses equals.... 

  1. negative square root of 2 

  2. negative 1 half square root of 2 

  3. 0

  4. 1 fourth square root of 2 

  5. square root of 2 

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

Jawaban yang benar adalah A

Pembahasan

Pembahasan

Limit trigonometri.

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as straight x rightwards arrow straight pi over 4 of open parentheses fraction numerator cos space 2 straight x over denominator sin space straight x space minus space cos space straight x end fraction close parentheses end cell equals cell limit as straight x rightwards arrow straight pi over 4 of open parentheses fraction numerator cos squared straight x minus sin squared straight x over denominator sin space straight x minus cos space straight x end fraction close parentheses end cell row blank equals cell limit as straight x rightwards arrow straight pi over 4 of left parenthesis fraction numerator left parenthesis cos space straight x minus sin space straight x right parenthesis left parenthesis cos space straight x plus sin space straight x right parenthesis over denominator sin space x space minus space cos space x end fraction right parenthesis end cell row blank equals cell limit as straight x rightwards arrow straight pi over 4 of open parentheses fraction numerator left parenthesis cos space straight x minus sin space straight x right parenthesis left parenthesis cos space straight x plus sin space straight x right parenthesis over denominator negative open parentheses cos space straight x space minus space sin space straight x close parentheses end fraction close parentheses end cell row blank equals cell limit as straight x rightwards arrow straight pi over 4 of minus open parentheses cos space straight x plus sin space straight x close parentheses end cell row blank equals cell limit as straight x rightwards arrow straight pi over 4 of minus cos space straight x minus space sin space straight x end cell row blank equals cell negative cos space straight pi over 4 minus sin space straight pi over 4 end cell row blank equals cell negative 1 half square root of 2 minus 1 half square root of 2 end cell row blank equals cell negative square root of 2 end cell end table 

Jadii, Error converting from MathML to accessible text. 

Oleh karena itu, Jawaban yang benar adalah A

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