Iklan

Pertanyaan

Nilai x yang memenuhi pertidaksamaan x + 1 x + 1 ​ > x − 1 x ​ adalah ...

Nilai x yang memenuhi pertidaksamaan  adalah ...

  1. x less than 1

  2. x greater than negative 1

  3. negative 1 less or equal than x less than 1

  4. x less than negative 1 space a t a u minus 1 less than x less than 1

  5. x less than negative 1 space a t a u space x greater than 1

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

04

:

30

:

17

Klaim

Iklan

N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Jawaban

penyelesaiannya adalah

penyelesaiannya adalah x less than negative 1 space a t a u minus 1 less than x less than 1

Pembahasan

Buat garis bilangan : Jadi penyelesaiannya adalah

fraction numerator x plus 1 over denominator x plus 1 end fraction greater than fraction numerator x over denominator x minus 1 end fraction fraction numerator x plus 1 over denominator x plus 1 end fraction minus fraction numerator x over denominator x minus 1 end fraction greater than 0 rightwards arrow s a m a k a n space p e n y e b u t fraction numerator open parentheses x minus 1 close parentheses open parentheses x plus 1 close parentheses minus x open parentheses x plus 1 close parentheses over denominator open parentheses x plus 1 close parentheses open parentheses x minus 1 close parentheses end fraction greater than 0 fraction numerator x squared minus 1 minus x squared minus x over denominator open parentheses x plus 1 close parentheses open parentheses x minus 1 close parentheses end fraction greater than 0 fraction numerator negative open parentheses x plus 1 close parentheses over denominator open parentheses x plus 1 close parentheses open parentheses x minus 1 close parentheses end fraction greater than 0 rightwards arrow k a l i k a n minus 1 fraction numerator x plus 1 over denominator open parentheses x plus 1 close parentheses open parentheses x minus 1 close parentheses end fraction less than 0  P e m b u a t space n o l colon x plus 1 equals 0 space space space space space space space space space a t a u space space space space space space x minus 1 equals 0 space space space space space space x equals negative 1 space space space space space space space space space space space space space space space space space space space space space space space space space x equals 1  space S y a r a t colon space p e n y e b u t space t i d a k space b o l e h space n o l comma space m a k a colon x plus 1 not equal to 0 space space space space space space space space space a t a u space space space space space space x minus 1 not equal to 0 space space space space space space x not equal to negative 1 space space space space space space space space space space space space space space space space space space space space space space space space space x not equal to 1

Buat garis bilangan : 

Jadi penyelesaiannya adalah x less than negative 1 space a t a u minus 1 less than x less than 1

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

Mita Aprilia

Bantu banget

Iklan

Pertanyaan serupa

Semua bilangan real x yang memenuhi x − 3 x ​ ≤ x + 2 x + 3 ​ adalah....

1

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia