Pertanyaan

Nilai dari x → − 3 lim x 2 + 7 x + 12 x + 12 − 3 = …

Nilai dari $x \to - 3 lim \frac{x + 12 - 3}{x ^{2} + 7 x + 12} = \dots$

H. Endah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah D.

Pembahasan

Nilainya didapatkan: Dengan demikian, nilai dari . Jadi, jawaban yang benar adalah D.

Nilainya didapatkan:

$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow negative 3 of space fraction numerator square root of x plus 12 end root minus 3 over denominator x squared plus 7 x plus 12 end fraction end cell equals cell limit as x rightwards arrow negative 3 of space fraction numerator square root of x plus 12 end root minus 3 over denominator x squared plus 7 x plus 12 end fraction times fraction numerator square root of x plus 12 end root plus 3 over denominator square root of x plus 12 end root plus 3 end fraction end cell row blank equals cell limit as x rightwards arrow negative 3 of space fraction numerator x plus 12 minus 9 over denominator open parentheses x squared plus 7 x plus 12 close parentheses open parentheses square root of x plus 12 end root plus 3 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow negative 3 of space fraction numerator up diagonal strike x plus 3 end strike over denominator up diagonal strike open parentheses x plus 3 close parentheses end strike open parentheses x plus 4 close parentheses open parentheses square root of x plus 12 end root plus 3 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow negative 3 of space fraction numerator 1 over denominator open parentheses x plus 4 close parentheses open parentheses square root of x plus 12 end root plus 3 close parentheses end fraction end cell row blank equals cell fraction numerator 1 over denominator open parentheses open parentheses negative 3 close parentheses plus 4 close parentheses open parentheses square root of open parentheses negative 3 close parentheses plus 12 end root plus 3 close parentheses end fraction end cell row blank equals cell fraction numerator 1 over denominator open parentheses 1 close parentheses open parentheses 3 plus 3 close parentheses end fraction end cell row blank equals cell 1 over 6 end cell end table$

Dengan demikian, nilai dari $limit as x rightwards arrow negative 3 of space fraction numerator square root of x plus 12 end root minus 3 over denominator x squared plus 7 x plus 12 end fraction equals 1 over 6$ .

Jadi, jawaban yang benar adalah D.