Pertanyaan

Nilai dari x → 0 lim 2 x . sin 2 x 1 − cos x = ....

Nilai dari $x \to 0 lim \frac{1 - cos x}{2 x . sin 2 x} = ....$

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Pembahasan

$Ingat space sifat comma limit as straight x rightwards arrow 0 of fraction numerator sin begin display style space end style begin display style ax end style over denominator bx end fraction equals limit as straight x rightwards arrow 0 of fraction numerator ax over denominator sin begin display style space end style begin display style bx end style end fraction equals straight a over straight b limit as straight x rightwards arrow 0 of fraction numerator sin begin display style space end style begin display style ax end style over denominator sin space bx end fraction equals limit as straight x rightwards arrow 0 of fraction numerator sin space ax over denominator sin begin display style space end style begin display style bx end style end fraction equals straight a over straight b sehingga limit as straight x rightwards arrow 0 of fraction numerator 1 minus cos invisible function application straight x over denominator 2 straight x space. space space sin invisible function application 2 straight x end fraction equals limit as straight x rightwards arrow 0 of fraction numerator 2 sin squared invisible function application open parentheses 1 half straight x close parentheses over denominator 2 straight x space. space space sin invisible function application 2 straight x end fraction equals limit as straight x rightwards arrow 0 of fraction numerator 2. sin invisible function application open parentheses 1 half straight x close parentheses. sin invisible function application open parentheses 1 half straight x close parentheses over denominator 2 straight x space. space space sin invisible function application 2 straight x end fraction equals limit as straight x rightwards arrow 0 of fraction numerator sin invisible function application open parentheses 1 half straight x close parentheses. sin invisible function application open parentheses 1 half straight x close parentheses over denominator straight x space. space space sin invisible function application 2 straight x end fraction equals limit as straight x rightwards arrow 0 of fraction numerator sin invisible function application open parentheses 1 half straight x close parentheses over denominator straight x end fraction. limit as straight x rightwards arrow 0 of fraction numerator sin invisible function application open parentheses 1 half straight x close parentheses over denominator sin invisible function application 2 straight x end fraction equals fraction numerator begin display style 1 half end style over denominator 1 end fraction. fraction numerator begin display style 1 half end style over denominator 2 end fraction equals 1 over 8$